Пример #1
0
 public static double CalculateDistance(Peak peak1, Peak peak2)
 {
     //http://stackoverflow.com/questions/6366408/calculating-distance-between-two-latitude-and-longitude-geocoordinates
     return MetersToMiles(peak1.geoCoordinate.GetDistanceTo(peak2.geoCoordinate));
 }
Пример #2
0
 public List<Peak> GetPeaksWithinDistanceNotVisited(Peak p, Stack<Peak> visited, double distance)
 {
     int index = peaks.IndexOf(p);
     var lookups = distanceLookup[index];
     var returnValues = new List<Peak>();
     for (int i = 0; i < lookups.Count; i++)
     {
         if (lookups[i] < distance)
         {
             if (visited.Contains(peaks[i]) || peaks[i].Equals(p))
             {
                 continue;
             }
             else
             {
                 returnValues.Add(peaks[i]);
             }
         }
     }
     return returnValues;
 }
Пример #3
0
 private void DebugPrint(Peak p, List<Peak> listOfPeaks)
 {
     for (int count = 0; count < listOfPeaks.Count; count++)
     {
         if (count < listOfPeaks.Count - 1)
         {
             Debug.WriteLine(" {0}, distance {1} ", listOfPeaks.ToArray()[count].name, CalculateDistance(listOfPeaks.ToArray()[count], p));
         }
         else
         {
             Debug.WriteLine(" " + listOfPeaks.ToArray()[count].name);
         }
     }
 }
Пример #4
0
        public void FindRoutesForPeak(Peak p, double distance, Stack<Peak> visited, List<List<Peak>> solutions)
        {
            if (progressCounter++ % 1000000 == 0)
            {
                Console.Write(".");
            }
            visited.Push(p);
            var nextPeaks = GetPeaksWithinDistanceNotVisited(p, visited, distance);

            if (nextPeaks.Count == 0)
            {
                //add to solutions
                if (solutions.Count > 0)
                {
                    if (solutions[0].Count <= visited.Count)
                    {
                        //always keep longest solutions in front
                        solutions.Insert(0, visited.ToList());
                    }
                }
                else
                {
                    solutions.Add(visited.ToList());
                }
                visited.Pop();
                return;
            }

            foreach (Peak next in nextPeaks)
            {
                FindRoutesForPeak(next, distance - CalculateDistance(p, next), visited, solutions);
            }
            visited.Pop();
            nextPeaks = null;
            return;
        }