C# (CSharp) Orleankka StreamPath.Deserialize примеры использования

Пример #1

        public StreamRef(SerializationInfo info, StreamingContext context)
        {
            var value = (string)info.GetValue("path", typeof(string));

            Path = StreamPath.Deserialize(value);
        }

Пример #2

 public static StreamRef Deserialize(string path) => Deserialize(StreamPath.Deserialize(path));