public XMLRepositoryBase(string fileName)
 {
     m_context = new Repository.XMLSource.XMLSet <TEntity>(fileName);
 }
Пример #2
0
 public KsiazkaXMLRepository()
     : base("ksiazka.xml")
 {
     m_context = new Repository.XMLSource.XMLSet <Ksiazka>("ksiazka.xml");
 }
Пример #3
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 public RozdzialXMLRepository()
     : base("rozdzial.xml")
 {
     m_context = new Repository.XMLSource.XMLSet <Rozdzial>("rozdzial.xml");
 }