Deserialize() публичный Метод

Deserialize the ROP response buffer.
public Deserialize ( byte ropBytes, int startIndex ) : int
ropBytes byte ROPs bytes in response.
startIndex int The start index of this ROP.
Результат int
 /// <summary>
 /// Parse bytes in context into TaggedPropertyValueNode
 /// </summary>
 /// <param name="context">The value of Context</param>
 public override void Parse(Context context)
 {
     // Parse PropertyType and assign it to context's current PropertyType
     Microsoft.Protocols.TestSuites.Common.PropertyTag p = new PropertyTag();
     context.CurIndex += p.Deserialize(context.PropertyBytes, context.CurIndex);
     context.CurProperty.Type = (PropertyType)p.PropertyType;
     this.PropertyTag = p;
     base.Parse(context);
 }
Пример #2
0
        /// <summary>
        /// Parse bytes in context into TaggedPropertyValueNode
        /// </summary>
        /// <param name="context">The value of Context</param>
        public override void Parse(Context context)
        {
            // Parse PropertyType and assign it to context's current PropertyType
            Microsoft.Protocols.TestSuites.Common.PropertyTag p = new PropertyTag();
            context.CurIndex        += p.Deserialize(context.PropertyBytes, context.CurIndex);
            context.CurProperty.Type = (PropertyType)p.PropertyType;

            // this.PropertyTag = new PropertyTag();
            this.PropertyTag = p;

            // context.CurIndex += this.PropertyTag.Deserialize(context.PropertyBytes, context.CurIndex);
            // context.CurProperty.Type = (PropertyType)this.PropertyTag.PropertyType;
            base.Parse(context);
        }