/// <summary>
        /// 移入
        /// </summary>
        /// <param name="send"></param>
        /// <param name="receive"></param>
        public static void OnEnter(DistanceInteraction send, DistanceInteraction receive)
        {
            //if (send.distanceData.IsOnly && send.OnlyDistance != receive) return;

            //在次之前,还需要判断一次,否则一直执行循环查找,会很费资源,这么处理不恰当
            if (send.OnlyDistance != null || !receive.OnInteractionCheck())
            {
                return;
            }

            //Debug.Log("进来-发送端:" + send.Interaction.FeaturesObjectController + " 接收端:" + receive.Interaction.FeaturesObjectController);

            InteractionDistanceInfo distanceInfo;

            if (IsContains(send, receive, out distanceInfo))
            {
                distanceInfo.SetDistanceStatus(DistanceStatus.Enter);
            }
            else
            {
                distanceInfo = new InteractionDistanceInfo(send, receive, DistanceStatus.Enter);
                DistanceInfos.Add(distanceInfo);
            }

            receive.OnInteractionEnter(send);
            send.OnInteractionEnter(receive);
        }
Пример #2
0
        /// <summary>
        /// 是否存在
        /// </summary>
        /// <param name="send"></param>
        /// <param name="receive"></param>
        /// <returns></returns>
        static bool IsContains(DistanceData send, DistanceData receive, out InteractionDistanceInfo distanceInfo)
        {
            var distance = DistanceInfos.Find(obj => obj.sendKey.Equals(send) && obj.receiveValue.Equals(receive));

            distanceInfo = distance;

            return(distance != null);
        }