Пример #1
0
 public ESProfileLogin(string identifier, ESAuthModule authModule, ESProfileLoginDetails details, AccessRecord?access = null)
 {
     Identifier = identifier;
     AuthModule = authModule;
     Details    = details;
     Access     = access;
 }
Пример #2
0
 public AuthModuleUsage(ESAuthModule authModule, int profiles)
 {
     AuthModule = authModule;
     Profiles   = profiles;
 }