Пример #1
0
 private void debugMenuItem_Click(object sender, EventArgs e)
 {
     using (DebugForm form = new DebugForm())
     {
         form.ShowDialog();
     }
 }
Пример #2
0
 public DebugPresenter(DebugForm form)
 {
     _form = form;
     AssembleDebugInfo();
 }