Пример #1
0
        public bool IsDependent(DependenceGraphNode n1, DependenceGraphNode n2)
        {
            if (n1 == null || n2 == null || n1 == n2)
            {
                return(false);
            }
            Dictionary <DependenceGraphNode, bool> oldNodes     = new Dictionary <DependenceGraphNode, bool>();
            Queue <DependenceGraphNode>            iterateQueue = new Queue <DependenceGraphNode>();

            iterateQueue.Enqueue(n1);
            oldNodes[n1] = true;
            while (iterateQueue.Count > 0)
            {
                DependenceGraphNode n = iterateQueue.Dequeue();
                foreach (DependenceGraphNode nn in n.NextNodes)
                {
                    if (nn == n2)
                    {
                        iterateQueue.Clear();
                        oldNodes.Clear();
                        return(true);
                    }
                    if (!oldNodes.ContainsKey(nn))
                    {
                        iterateQueue.Enqueue(nn);
                        oldNodes[nn] = true;
                    }
                }
            }
            return(false);
        }
Пример #2
0
 public bool IsAccessed(DependenceGraphNode node)
 {
     if (accessedNodes.ContainsKey(node))
     {
         return(accessedNodes[node]);
     }
     return(false);
 }
Пример #3
0
 public DependenceGraphNode NewNode(string id)
 {
     if (nodes.ContainsKey(id))
     {
         return(nodes[id]);
     }
     else
     {
         DependenceGraphNode node = new DependenceGraphNode(id);
         nodes[id] = node;
         return(node);
     }
 }
Пример #4
0
        private DependenceGraphNode PopDeepFirstNode()
        {
            if (iterateStack.Count <= 0)
            {
                return(null);
            }
            DependenceGraphNode node = iterateStack.Peek();

            while (node.NextNodes.Count > 0)
            {
                bool existNext = false;
                //每次只扩展一个后继,深度优先
                for (int i = 0; i < node.NextNodes.Count; i++)
                {
                    DependenceGraphNode n = node.NextNodes[i];
                    if (!accessedNodes.ContainsKey(n))
                    {
                        iterateStack.Push(n);
                        PrepareAccessNode(n);
                        existNext = true;
                        break;
                    }
                    else if (!accessedNodes[n])//依赖一个存于深度优先栈内的节点,表明有循环依赖
                    {
                        cyclicDependences.Add(new KeyValuePair <string, string>(node.ID, n.ID));
                    }
                }
                if (!existNext)
                {
                    break;
                }
                else
                {
                    node = iterateStack.Peek();
                }
            }
            node = iterateStack.Pop();
            return(node);
        }
Пример #5
0
 /// <summary>
 /// 设定一个结点为已访问结点,已访问结点是已经由迭代过程返回过的结点。
 /// </summary>
 /// <param name="node"></param>
 private void AccessNode(DependenceGraphNode node)
 {
     accessedNodes[node] = true;
 }
Пример #6
0
 /// <summary>
 /// 设定一个结点为待访问结点,同时从未访问集合中删除此结点。
 /// </summary>
 /// <param name="node"></param>
 private void PrepareAccessNode(DependenceGraphNode node)
 {
     accessedNodes[node] = false;
     unaccessedNodes.Remove(node);
 }