Пример #1
0
        // 同じソース内に複数の問題の解答も書いているので、Employee2というクラスを定義して、それを利用している。
        private static void Exercise1_4(string file)
        {
            var emps = new Employee2[] {
                new Employee2 {
                    Id       = 123,
                    Name     = "出井 秀行",
                    HireDate = new DateTime(2001, 5, 10)
                },
                new Employee2 {
                    Id       = 139,
                    Name     = "大橋 孝仁",
                    HireDate = new DateTime(2004, 12, 1)
                },
            };

            using (var stream = new FileStream(file, FileMode.Create,
                                               FileAccess.Write)) {
                // DateTimeの書式を変更することもできる。
                var serializer = new DataContractJsonSerializer(
                    emps.GetType(),
                    new DataContractJsonSerializerSettings {
                    DateTimeFormat = new DateTimeFormat("yyyy-MM-dd'T'HH:mm:ssZ")
                }
                    );

                serializer.WriteObject(stream, emps);
            }
        }
Пример #2
0
        static void Main(string[] args)
        {
            var employee = new Employee {
                Id = 1, Name = "James", HireDate = new DateTime(1980, 2, 28)
            };

            // 12.1.1
            var settings = new XmlWriterSettings
            {
                Encoding    = new UTF8Encoding(false),
                Indent      = true,
                IndentChars = "    ",
            };

            using (var writer = XmlWriter.Create("employee.xml", settings))
            {
                var serializer = new XmlSerializer(employee.GetType());
                serializer.Serialize(writer, employee);
            }

            // 12.1.2
            var employees = new List <Employee> {
            };

            employees.Add(employee);
            employees.Add(new Employee {
                Id = 2, Name = "Kirby", HireDate = new DateTime(2018, 2, 28)
            });

            using (var writer = XmlWriter.Create("employees.xml", settings))
            {
                var serializer = new DataContractSerializer(employees.GetType());
                serializer.WriteObject(writer, employees);
            }

            // 12.1.3
            using (XmlReader reader = XmlReader.Create("employees.xml"))
            {
                var serializer            = new DataContractSerializer(typeof(Employee[]));
                var desirializedEmployees = serializer.ReadObject(reader) as Employee[];
                desirializedEmployees.ToList()
                .ForEach(e => Console.WriteLine($"{e.Id.ToString()}\t{e.Name}\t{e.HireDate.ToString()}"));
            }

            // 12.1.4
            var employees2 = new Employee2[]
            {
                new Employee2 {
                    Id = 3, Name = "Mai", HireDate = new DateTime(2016, 9, 4)
                },
                new Employee2 {
                    Id = 4, Name = "Azrael", HireDate = new DateTime(2016, 9, 7)
                },
            };

            using (var stream = new FileStream("enployee2.json", FileMode.Create, FileAccess.Write))
            {
                var serializer = new DataContractJsonSerializer(employees2.GetType());
                serializer.WriteObject(stream, employees2);
            }
        }