//Finds the best onsuit play, which is win with the worst of the best, or just go with the worst
//It's given that there's at least two valid moves. Must return a valid move
public int findOnsuitPlay(Trick currentTrick, ArrayList validMoves)
{
int index = 0;
bool winnable = false;
for (int i = 0; i < validMoves.Count; i++)
{
//If we can beat the current card
if (isBetterCard(currentTrick.getMoves()[currentTrick.currentWinner], (Card)validMoves[i], currentTrick.trumpSuit))
{
//There was no previous winning card
if (!winnable)
{
winnable = true;
index = i;
}
//There is already a winnable card
else
{
//If the old card can beat the new card, we want to use the new one to save the better
if (isBetterCard((Card)validMoves[i], (Card)validMoves[index], currentTrick.trumpSuit))
{
index = i;
}
}
}
//This card can't beat the current card, and there isn't yet a card that can
else if (!winnable)
{
//If the old card can beat the new card, we want to use the new to save our better one
if (isBetterCard((Card)validMoves[i], (Card)validMoves[index], currentTrick.trumpSuit))
{
index = i;
}
}
}
return(index);
}
public void updatedCardCount(Trick pastTrick)
{
counter.removeGroup(new ArrayList(pastTrick.getMoves()));
}
