parse() публичный Метод

public parse ( FileStream source ) : void
source System.IO.FileStream
Результат void
Пример #1
0
 public DMimage(String Filename)
 {
     DMIParser parser = new DMIParser();
     parser.parse(new FileStream(Filename, FileMode.Open, FileAccess.Read));
     states = parser.states;
     width = parser.width;
     height = parser.height;
 }
Пример #2
0
        public DMimage(String Filename)
        {
            DMIParser parser = new DMIParser();

            parser.parse(new FileStream(Filename, FileMode.Open, FileAccess.Read));
            states = parser.states;
            width  = parser.width;
            height = parser.height;
        }