Пример #1
0
 private void load(object sender, EventArgs e)
 {
     OpenFileDialog dialog = new OpenFileDialog();
     DirectoryInfo di = new DirectoryInfo(Directory.GetCurrentDirectory() + @"\..\..\Test\XMLStore");
     dialog.InitialDirectory = di.FullName;
     dialog.DefaultExt = "*.xml";
     if (dialog.ShowDialog(this) != DialogResult.OK) return;
     helper = new DiagramHelper();
     helper.DeserializeFromXMLFile(dialog.FileName);
 }