Пример #1
0
 public LineGraph(string title, string subTitle, DataPointFormat dataPointFormat, IEnumerable <Line> lines)
 {
     this.Title           = title;
     this.SubTitle        = subTitle;
     this.DataPointFormat = dataPointFormat;
     this.Lines           = new List <Line>(lines);
 }
Пример #2
0
 public LineGraph(string title, string subTitle, DataPointFormat dataPointFormat, params Line[] lines)
     : this(title, subTitle, dataPointFormat, (IEnumerable <Line>)lines)
 {
 }