Пример #1
0
 private void pictureBoxB_DoubleClick(object sender, EventArgs e)
 {
     OutForm = new ImageOutForm((Bitmap)this.pictureBoxB.Image);
     OutForm.ShowDialog();
 }
Пример #2
0
 private void picBoxOriginal_DoubleClick(object sender, EventArgs e)
 {
     OutForm = new ImageOutForm((Bitmap)picBoxOriginal.Image);
     OutForm.ShowDialog();
 }