Пример #1
0
        public virtual bool Check()
        {
            if (!NumberLimitRule.Check(NumberLimit, Pokers.Count))
            {
                return(false);
            }

            if (!Pokers.All(x => x.Display == Pokers.First().Display))
            {
                return(false);
            }

            return(true);
        }
Пример #2
0
        public bool Check()
        {
            if (!NumberLimitRule.Check(NumberLimit, Pokers.Count))
            {
                return(false);
            }

            var pokerKeys = Pokers.Select(x => x.Display).Distinct();

            if (pokerKeys.Count() != 2)
            {
                return(false);
            }

            return(Pokers.Count(x => x.Display == pokerKeys.First()) == 3 || Pokers.Count(x => x.Display == pokerKeys.Last()) == 3);
        }
Пример #3
0
        public bool Check()
        {
            if (!NumberLimitRule.Check(NumberLimit, Pokers.Count))
            {
                return(false);
            }

            //不能包含大小王和2

            //不能有相同
            for (var i = 1; i < Pokers.Count; i++)
            {
                if (Pokers[i].Weight == Pokers.First().Weight)
                {
                    return(false);
                }
            }

            //连续的,这里是最大的减去最小的等于一个值
            return(Pokers.Max(x => x.Weight) - Pokers.Min(x => x.Weight) == Pokers.Count - 1);
        }
Пример #4
0
        public bool Check()
        {
            if (!NumberLimitRule.Check(NumberLimit, Pokers.Count))
            {
                return(false);
            }
            //判断数目是否是偶数
            if (Pokers.Count % 2 != 0)
            {
                return(false);
            }

            //不能包含大小王和2
            if (!Pokers.Select(x => x.Display).Distinct().All(x => Pokers.Count(y => y.Display == x) == 2))
            {
                return(false);
            }

            //判断牌是否是连续的,这里是最大的减去最小的等于一个值
            return(Pokers.Max(x => x.Weight) - Pokers.Min(x => x.Weight) == Pokers.Count - 1);
        }