ShowDialog() публичный Метод

public ShowDialog ( ) : void
Результат void
Пример #1
0
        private void btnAppGrabber_Click(object sender, RoutedEventArgs e)
        {
            if (MenuBar != null)
            {
                MenuBar.ProgramsMenu.IsSubmenuOpen = false;
            }

            appGrabber.ShowDialog();
        }
Пример #2
0
 private void InitAppGrabberWindow(object sender, RoutedEventArgs e)
 {
     appGrabber.ShowDialog();
 }