showControls() публичный Метод

public showControls ( ) : void
Результат void
Пример #1
0
	    public static void setDocActive(cEditor editor) {
	        m_editor = editor;
	        setMenu();
            if (editor != null)
            {
                TabPage editorTab = editor.getEditorTab();
                (editorTab.Parent as TabControl).SelectedTab = editorTab;

                if (m_fToolbox != null && !m_fToolbox.IsDisposed && m_fToolbox.Visible)
                {
                    if (getToolbox(editor) != null) { editor.showToolbox(); }
                }
                if (m_fControls != null && !m_fControls.IsDisposed && m_fControls.Visible)
                {
                    if (getCtrlBox(editor) != null) { editor.showControls(); }
                }
                if (m_fTreeViewCtrls != null && !m_fTreeViewCtrls.IsDisposed && m_fTreeViewCtrls.Visible)
                {
                    if (getCtrlTreeBox(editor) != null) { editor.showControlsTree(); }
                }
            }
            else
            {
                if (m_fToolbox != null && !m_fToolbox.IsDisposed && m_fToolbox.Visible)
                {
                    m_fToolbox.clear();
                }
                if (m_fControls != null && !m_fControls.IsDisposed && m_fControls.Visible)
                {
                    m_fControls.clear();
                }
                if (m_fTreeViewCtrls != null && !m_fTreeViewCtrls.IsDisposed && m_fTreeViewCtrls.Visible)
                {
                    m_fTreeViewCtrls.clear();
                }
            }
            fmain.showControls(editor);
            fmain.showControlsTree(editor);
            fmain.showFields(editor);
        }