internal static IntervalCollection <T> HighUnionOf <T>(IntervalCollection <T> collection)
{
if (collection == null)
{
throw new ArgumentNullException("collection");
}
if (collection.Count == 0)
{
return(collection);
}
var result = new List <Interval <T> > {
collection[0]
};
for (int i = 1; i < collection.Count; i++)
{
var interval = collection[i];
var col = new List <Interval <T> >(result);
result = new List <Interval <T> >(collection.Count);
foreach (var item in col)
{
var u = Interval.HighUnionOf(item, interval);
if (u.Count != 1)
{
result.AddRange(u);
}
else
{
result.RemoveAll(match => match == item || match == interval);
result.AddRange(u);
interval = u[0];
}
}
result = new List <Interval <T> >(result.Distinct());
}
result.Sort();
return(new IntervalCollection <T>(result));
}
/// <summary>
/// Gets the union of the current <see cref="T:IntervalCollection`1"/> according to the specified <paramref name="denominator"/>.
/// </summary>
/// <param name="denominator">The denominator considered while performing the union.</param>
/// <value>The union.</value>
/// <remarks>
/// While performing an <see cref="Interval.UnionOf<T>">UnionOf</see> intervals, depending of the specified <see cref="UnionDenominator"/>, the result will be different.
/// If you consider the following intervals:
/// <list type="table">
/// <item>
/// <term>a</term>
/// <description>]∞ ; 3[</description>
/// </item>
/// <item>
/// <term>b</term>
/// <description>]0 ; 5[</description>
/// </item>
/// <item>
/// <term>c</term>
/// <description>[1 ; 2]</description>
/// </item>
/// </list>
/// The union with the <see cref="UnionDenominator.Highest"/> denominator will return an <see cref="IntervalCollection<T>"/> of 1 element as shown below:
/// <list type="table">
/// <item>
/// <term>i</term>
/// <description>]∞ ; 5[</description>
/// </item>
/// </list>
/// The union with the <see cref="UnionDenominator.Lowest"/> denominator will return an <see cref="IntervalCollection<T>"/> of 5 element as shown below:
/// <list type="table">
/// <item>
/// <term>i</term>
/// <description>]∞ ; 0]</description>
/// </item>
/// <item>
/// <term>j</term>
/// <description>]0 ; 1[</description>
/// </item>
/// <item>
/// <term>k</term>
/// <description>[1 ; 2]</description>
/// </item>
/// <item>
/// <term>l</term>
/// <description>]2 ; 3[</description>
/// </item>
/// <item>
/// <term>m</term>
/// <description>[3 ; 5[</description>
/// </item>
/// </list>
/// </remarks>
public IntervalCollection <T> Union(UnionDenominator denominator)
{
return((denominator == UnionDenominator.Highest)
? Interval.HighUnionOf(this)
: Interval.LowUnionOf(this));
}