// Note: see -
// http://logic.stanford.edu/classes/cs157/2008/lectures/lecture15.pdf
// slide 12 for where this test example was taken from.
public static FOLKnowledgeBase CreateAbcEqualityKnowledgeBase(
IInferenceProcedure infp, bool includeEqualityAxioms)
{
var domain = new FOLDomain();
domain.AddConstant("A");
domain.AddConstant("B");
domain.AddConstant("C");
var kb = new FOLKnowledgeBase(domain, infp);
kb.tell("B = A");
kb.tell("B = C");
if (includeEqualityAxioms)
{
// Reflexivity Axiom
kb.tell("x = x");
// Symmetry Axiom
kb.tell("(x = y => y = x)");
// Transitivity Axiom
kb.tell("((x = y AND y = z) => x = z)");
}
return(kb);
}
public static FOLKnowledgeBase CreateRingOfThievesKnowledgeBase(
IInferenceProcedure infp)
{
var kb = new FOLKnowledgeBase(DomainFactory.RingOfThievesDomain(), infp);
// s(x) => ~c(x) One who skis never gets caught
kb.tell("(Skis(x) => NOT(Caught(x)))");
// c(x) => ~s(x) Those who are caught don't ever ski
kb.tell("(Caught(x) => NOT(Skis(x)))");
// p(x,y) & c(y) => s(x) Jailbird parents have skiing kids
kb.tell("((Parent(x,y) AND Caught(y)) => Skis(x))");
// s(x) & f(x,y) => s(y) All friends ski together
kb.tell("(Skis(x) AND Friend(x,y) => Skis(y))");
// f(x,y) => f(y,x) Friendship is symmetric
kb.tell("(Friend(x,y) => Friend(y,x))");
// FACTS
// 1. { p(Mike,Joe) } Premise
kb.tell("Parent(Mike, Joe)");
// 2. { p(Janet,Joe) } Premise
kb.tell("Parent(Janet,Joe)");
// 3. { p(Nancy,Mike) } Premise
kb.tell("Parent(Nancy,Mike)");
// 4. { p(Ernie,Janet) } Premise
kb.tell("Parent(Ernie,Janet)");
// 5. { p(Bert,Nancy) } Premise
kb.tell("Parent(Bert,Nancy)");
// 6. { p(Red,Ernie) } Premise
kb.tell("Parent(Red,Ernie)");
// 7. { f(Red,Bert) } Premise
kb.tell("Friend(Red,Bert)");
// 8. { f(Drew,Nancy) } Premise
kb.tell("Friend(Drew,Nancy)");
// 9. { c(Mike) } Premise
kb.tell("Caught(Mike)");
// 10. { c(Ernie) } Premise
kb.tell("Caught(Ernie)");
return(kb);
}
public static FOLKnowledgeBase CreateKingsKnowledgeBase(
IInferenceProcedure infp)
{
FOLKnowledgeBase kb = new FOLKnowledgeBase(DomainFactory.KingsDomain(),
infp);
kb.tell("((King(x) AND Greedy(x)) => Evil(x))");
kb.tell("King(John)");
kb.tell("King(Richard)");
kb.tell("Greedy(John)");
return(kb);
}
public static FOLKnowledgeBase CreateLovesAnimalKnowledgeBase(
IInferenceProcedure infp)
{
FOLKnowledgeBase kb = new FOLKnowledgeBase(DomainFactory
.LovesAnimalDomain(), infp);
kb
.tell("FORALL x (FORALL y (Animal(y) => Loves(x, y)) => EXISTS y Loves(y, x))");
kb
.tell("FORALL x (EXISTS y (Animal(y) AND Kills(x, y)) => FORALL z NOT(Loves(z, x)))");
kb.tell("FORALL x (Animal(x) => Loves(Jack, x))");
kb.tell("(Kills(Jack, Tuna) OR Kills(Curiosity, Tuna))");
kb.tell("Cat(Tuna)");
kb.tell("FORALL x (Cat(x) => Animal(x))");
return(kb);
}
public static FOLKnowledgeBase CreateWeaponsKnowledgeBase(
IInferenceProcedure infp)
{
FOLKnowledgeBase kb = new FOLKnowledgeBase(DomainFactory
.WeaponsDomain(), infp);
kb
.tell("( (((American(x) AND Weapon(y)) AND Sells(x,y,z)) AND Hostile(z)) => Criminal(x))");
kb.tell(" Owns(Nono, M1)");
kb.tell(" Missile(M1)");
kb.tell("((Missile(x) AND Owns(Nono,x)) => Sells(West,x,Nono))");
kb.tell("(Missile(x) => Weapon(x))");
kb.tell("(Enemy(x,America) => Hostile(x))");
kb.tell("American(West)");
kb.tell("Enemy(Nono,America)");
return(kb);
}
// Note: see -
// http://logic.stanford.edu/classes/cs157/2008/lectures/lecture15.pdf
// slide 16,17, and 18 for where this test example was taken from.
public static FOLKnowledgeBase CreateAbcdEqualityAndSubstitutionKnowledgeBase(
IInferenceProcedure infp, bool includeEqualityAxioms)
{
var domain = new FOLDomain();
domain.AddConstant("A");
domain.AddConstant("B");
domain.AddConstant("C");
domain.AddConstant("D");
domain.AddPredicate("P");
domain.AddFunction("F");
var kb = new FOLKnowledgeBase(domain, infp);
kb.tell("F(A) = B");
kb.tell("F(B) = A");
kb.tell("C = D");
kb.tell("P(A)");
kb.tell("P(C)");
if (includeEqualityAxioms)
{
// Reflexivity Axiom
kb.tell("x = x");
// Symmetry Axiom
kb.tell("(x = y => y = x)");
// Transitivity Axiom
kb.tell("((x = y AND y = z) => x = z)");
// Function F Substitution Axiom
kb.tell("((x = y AND F(y) = z) => F(x) = z)");
// Predicate P Substitution Axiom
kb.tell("((x = y AND P(y)) => P(x))");
}
return(kb);
}
