Пример #1
0
        private void ShowNewForm(object sender, EventArgs e)
        {
            openDBFileDialog.InitialDirectory = Application.StartupPath;
            openDBFileDialog.Filter           = "MS Access files (*.mdb)|*.mdb";
            if (openDBFileDialog.ShowDialog(this) == DialogResult.OK)
            {
                String fileName = openDBFileDialog.FileName;
                databasename           = System.IO.Path.GetFileNameWithoutExtension(fileName);
                strokendiagramFileName = System.IO.Path.GetDirectoryName(fileName) + "\\" + databasename + ".png";
                if (System.IO.File.Exists(strokendiagramFileName))
                {
                    strokendiagramToolStripMenuItem.Enabled = true;
                }

                CloseDatabase();
                if (OpenDatabase(fileName))
                {
                    DBForm childForm = new DBForm(connection);
                    childForm.MdiParent = this;
                    childForm.Text      = databasename;
                    childForm.Show();

                    sqlMenuItem.Enabled            = true;
                    databaseMenuItem.Enabled       = true;
                    closeToolStripMenuItem.Enabled = true;
                    toolStripStatusLabel.Text      = "Actieve database: " + fileName;
                }
            }
        }
Пример #2
0
        private void databaseMenuItem_Click(object sender, EventArgs e)
        {
            DBForm childForm = new DBForm(connection);

            childForm.MdiParent = this;
            childForm.Text      = databasename;
            childForm.Show();
        }