public bool UploadFile(string FileName, System.IO.Stream FileData)
{
ToolsManager.DataServices.Client.FileServiceProxy.UploadRequest inValue = new ToolsManager.DataServices.Client.FileServiceProxy.UploadRequest();
inValue.FileName = FileName;
inValue.FileData = FileData;
ToolsManager.DataServices.Client.FileServiceProxy.UploadResponse retVal = ((ToolsManager.DataServices.Client.FileServiceProxy.IFileUploadService)(this)).UploadFile(inValue);
return(retVal.Succeeded);
}
ToolsManager.DataServices.Client.FileServiceProxy.UploadResponse ToolsManager.DataServices.Client.FileServiceProxy.IFileUploadService.UploadFile(ToolsManager.DataServices.Client.FileServiceProxy.UploadRequest request)
{
return(base.Channel.UploadFile(request));
}
