Пример #1
0
        private void btnSubmit_Click(object sender, EventArgs e)
        {
            string id         = tbRestId.Text;
            var    restResult = RestaurantController.GetRestaurant(id);

            if (restResult != null)
            {
                var ds = ReviewController.GetSomeReview(id);
                dataGridView1.DataSource = ds;
            }
            else
            {
                MessageBox.Show("Review Not Found");
            }
        }