C# (CSharp) OpenWeatherService.GetForcastWeatherByCityName примеры использования

Пример #1

        public void OpenWeatherByCityName(string city)
        {
            var forcast = _openWeatherService.GetForcastWeatherByCityName(city, OpenWeatherService.ResponseFormat.Json);
            var responseCodeWeatherApp = (string)forcast.cod;

            responseCodeWeatherApp.Should().Be("200", $"The weather app was not able to get forcast for city: {city}");
        }