Пример #1
0
    /**
     * Retrieves the OpenSocial ID associated with the instance. Returns an
     * empty string if no ID has been set.
     */
    public String getId()
    {
        OpenSocialField IDField = this.getField("id");

        if (IDField != null && !IDField.isComplex())
        {
            return(IDField.getStringValue());
        }

        return("");
    }
Пример #2
0
    /**
     * Retrieves the display name (typically given name followed by family name)
     * associated with the instance. Returns an empty string if no name has been
     * set.
     *
     * @throws OpenSocialException
     */
    public String getDisplayName()
    {
        OpenSocialField nicknameField = this.getField("nickname");
        OpenSocialField nameField     = this.getField("name");
        StringBuilder   name          = new StringBuilder();

        if (nameField != null)
        {
            if (nameField.isComplex())
            {
                OpenSocialObject nameObject = nameField.getValue();

                if (nameObject.hasField("givenName"))
                {
                    name.Append(nameObject.getField("givenName").getStringValue());
                }

                if (nameObject.hasField("givenName") &&
                    nameObject.hasField("familyName"))
                {
                    name.Append(" ");
                }

                if (nameObject.hasField("familyName"))
                {
                    name.Append(nameObject.getField("familyName").getStringValue());
                }
            }
            else
            {
                name.Append(nameField.getStringValue());
            }
        }
        else if (nicknameField != null)
        {
            if (!nicknameField.isComplex())
            {
                name.Append(nicknameField.getStringValue());
            }
        }

        return(name.ToString());
    }
Пример #3
0
    /**
     * Recursively iterates through the properties of the passed JsonObject
     * object and returns a Map of OpenSocialField objects keyed on Strings
     * representing the property values and names respectively.
     *
     * @param  o Object-oriented representation of a JSON object which is
     *         transformed into and returned as a Map of OpenSocialField
     *         objects keyed on Strings
     * @throws JSONException
     */
    private static Dictionary <String, OpenSocialField> createObjectRepresentation(
        JsonObject o)
    {
        Dictionary <String, OpenSocialField> r = new Dictionary <String, OpenSocialField>();

        var keys = o.Names;

        foreach (string key in keys)
        {
            String property = o[key].ToString();

            if (property.Length > 0 && property[0] == '{')
            {
                JsonObject      p     = o.getJSONObject(key);
                OpenSocialField field = new OpenSocialField(true);

                field.addValue(new OpenSocialObject(createObjectRepresentation(p)));
                r.Add(key, field);
            }
            else if (property.Length > 0 && property[0] == '[')
            {
                JsonArray       p      = (JsonArray)o[key];
                var             values = createArrayRepresentation(p);
                OpenSocialField field  = new OpenSocialField(true);

                foreach (var v in values)
                {
                    field.addValue(v);
                }

                r.Add(key, field);
            }
            else if (property.Length > 0)
            {
                OpenSocialField field = new OpenSocialField(false);
                field.addValue(unescape(property));
                r.Add(key, field);
            }
        }

        return(r);
    }
Пример #4
0
 /**
  * Creates a new entry in fields Map, associating the passed OpenSocialField
  * object with the passed key.
  *
  * @param  key Field name
  * @param  value OpenSocialField object to associate with key
  */
 public void setField(String key, OpenSocialField value)
 {
     this.fields.Add(key, value);
 }
Пример #5
0
 /**
  * Creates a new entry in fields Map, associating the passed OpenSocialField
  * object with the passed key.
  * 
  * @param  key Field name
  * @param  value OpenSocialField object to associate with key
  */
 public void setField(String key, OpenSocialField value) {
   this.fields.Add(key, value);
 }
Пример #6
0
  /**
   * Recursively iterates through the properties of the passed JsonObject
   * object and returns a Map of OpenSocialField objects keyed on Strings
   * representing the property values and names respectively.
   * 
   * @param  o Object-oriented representation of a JSON object which is
   *         transformed into and returned as a Map of OpenSocialField
   *         objects keyed on Strings
   * @throws JSONException
   */
  private static Dictionary<String, OpenSocialField> createObjectRepresentation(
      JsonObject o)
    {

    Dictionary<String,OpenSocialField> r = new Dictionary<String,OpenSocialField>();

    var keys = o.Names;

      foreach (string key in keys)
      {
        String property = o[key].ToString();

      if (property.Length > 0 && property[0] == '{') {
        JsonObject p = o.getJSONObject(key);
        OpenSocialField field = new OpenSocialField(true);

        field.addValue(new OpenSocialObject(createObjectRepresentation(p)));
        r.Add(key, field);
      } else if (property.Length > 0 && property[0] == '[') {
        JsonArray p = (JsonArray)o[key];
        var values = createArrayRepresentation(p);
        OpenSocialField field = new OpenSocialField(true);

        foreach(var v in values) {
          field.addValue(v);
        }

        r.Add(key, field);
      } else if (property.Length > 0) {
        OpenSocialField field = new OpenSocialField(false);
        field.addValue(unescape(property));
        r.Add(key, field);
      }      
    }

    return r;
  }