Пример #1
0
    public Color GetNextLetterColor(bool _selecting, LetterBehaviour letter)
    {
        Color output;

        if (userWord.Count == 0)
        {
            output = Color.green;
        }
        else
        {
            output = Color.red;
        }

        if (!_selecting)
        {
            userWord.Add(letter);

            TryEndCondition();
        }
        else
        {
            int index      = userWord.IndexOf(letter);
            int wordLength = userWord.Count - 1;

            for (int i = wordLength; i >= index; i--)
            {
                userWord[i].Deselect();
                userWord.Remove(userWord[i]);
            }
        }
        return(output);
    }
Пример #2
0
 public Connection()
 {
     connectionRenderer = null;
     A           = null;
     B           = null;
     Initialized = false;
 }
Пример #3
0
    public Connection(LetterBehaviour _A, LetterBehaviour _B, LineRenderer _renderer)
    {
        connectionRenderer = _renderer;
        connectionRenderer.SetPosition(0, _A.GetCustomPosition());
        connectionRenderer.SetPosition(1, _B.GetCustomPosition());

        A           = _A;
        B           = _B;
        Initialized = true;
    }
Пример #4
0
    public bool IsConnected(LetterBehaviour nextLetter)
    {
        if (userWord.Count == 0)
        {
            return(true);
        }

        if (connections.HasConnection(userWord[userWord.Count - 1], nextLetter))
        {
            return(true);
        }

        return(false);
    }
Пример #5
0
    //Force algorithm : fix
    public bool HasConnection(LetterBehaviour A, LetterBehaviour B)
    {
        for (int i = 0; i < letterGraph.GetLength(0); i++)
        {
            for (int j = 0; j < letterGraph.GetLength(1); j++)
            {
                if (letterGraph[i, j].A == null)
                {
                    continue;
                }

                if (letterGraph[i, j].A == A && letterGraph[i, j].B == B)
                {
                    return(true);
                }

                if (letterGraph[i, j].A == B && letterGraph[i, j].B == A)
                {
                    return(true);
                }
            }
        }
        return(false);
    }
Пример #6
0
    private void AddLetterToArea(LetterBehaviour letter)
    {
        Vector3 pos = cameraArea.GetRandomPoint(letter);

        letter.gameObject.transform.position = pos;
    }