Пример #1
0
        private int isBrecket(int wordNomber, ISentence sent, LongOperationAttribut attr)
        {
            string word = sent.get_Word(wordNomber).WordStr;

            for (int i = 0; i < attr.attributSequence.Count; i++)
            {
                if (attr.attributSequence[i] is Brackets)
                {
                    Brackets br = attr.attributSequence[i] as Brackets;
                    if ((br.atribut1.word == word) || (br.atribut2.word == word))
                    {
                        return(i);
                    }
                    for (int j = 0; j < br.unionsForAttr2.Count; j++)
                    {
                        if ((br.unionsForAttr2[j] as ElementaryAttribut).word == word)
                        {
                            return(i);
                        }
                    }
                }
            }
            return(-1);
        }