Пример #1
0
        private void formToolStripMenuItem_Click(object sender, EventArgs e)
        {
            InsertFormDialog dlgInsertForm = new InsertFormDialog();

            dlgInsertForm.ExistingFormNames = builder.GetFormNames();
            if (dlgInsertForm.ShowDialog() == DialogResult.OK)
            {
                builder.InsertForm(dlgInsertForm.FormName, dlgInsertForm.FormAction,
                                   dlgInsertForm.FormMethod);
            }
        }