public void TestImageProcessor()
{
var ip = new GalleryImageProcessor();
OriginalImage img = new OriginalImage();
img.Filename = @"C:\Users\Ken\Documents\GitHub\SimplePhotoGallery\SimplePhotoGallery\Galleries\Canon1IMG_0050.JPG";
img.Title = "Renee smiling";
ip.ProcessPostUpload(img);
// now we should test that we have four thumbnails:
// large, medium, small and tiny
GalleryContext db = new GalleryContext();
var originalImage = db.Images.ToList();
// .Where(b => b.Title.Contains("James")).ToList();
/*
* .FirstOrDefault();
* .Include("ProcessedImages")
*
*/
foreach (var processedImage in originalImage)
{
var fn = processedImage.Filename;
}
}
// Upload entire file
private void UploadWholeFile(HttpContext context, List <FilesStatus> statuses)
{
// hack to see if thumbnails can be added
//Thumbnail tn = new Thumbnail();
//tn.Description = "medium";
//tn.MaxWidth = 600;
//db.Thumbnails.Add(tn);
//db.SaveChanges();
// in a controller we would probably use data binding
if (context.Request.Form["uploadDestination"] != "")
{
// this changes value of StorageRoot
GalleryDirectory = "~/" + context.Request.Form["uploadDestination"] + "/";
}
else
{
GalleryDirectory = "~/" + ConfigurationManager.AppSettings["uploadDestination"] + "/";
}
for (int i = 0; i < context.Request.Files.Count; i++)
{
var file = context.Request.Files[i];
// todo, see if this is really the right approach
var fullPath =
Path.Combine(StorageRoot, Path.GetFileName(file.FileName));
// hack using the file name to access the title field via the file name
var fileTitle = context.Request.Form[file.FileName.Replace(" ", "").Replace(".", "")];
// the file title is a description
try
{
GalleryImageProcessor ip = new GalleryImageProcessor();
OriginalImage img = new OriginalImage();
img.Filename = fullPath;
img.Title = fileTitle;
// todo, see if there are better ways of generating this url
img.UrlPath = GalleryDirectory + "/" + Path.GetFileName(file.FileName);
// todo, put this saving into the image as I had a bug where no
// files were saved because I omitted this step.
file.SaveAs(img.Filename);
ip.ProcessPostUpload(img);
string fullName = Path.GetFileName(file.FileName);
statuses.Add(new FilesStatus(fullName, file.ContentLength, fullPath));
}
catch (Exception e)
{
// todo, find out how to report the error to the web page
context.Response.Write("<p>Exception " + e.Message + "</p>");
}
}
}
