Пример #1
0
        private void HandleMessage(DirectTcpIpMessage message)
        {
            var channel = HandleChannelOpenMessage(message);
            var args    = new TcpRequestArgs(channel,
                                             message.Host,
                                             (int)message.Port,
                                             message.OriginatorIPAddress,
                                             (int)message.OriginatorPort,
                                             _auth);

            TcpForwardRequest?.Invoke(this, args);
        }
Пример #2
0
 private void HandleMessage(DirectTcpIpMessage message)
 {
     HandlePortForward(message, message.Host, message.Port, message.OriginatorIPAddress, message.OriginatorPort);
 }