Пример #1
0
        public WorldScreenMap(DataViewForm parent, WorldScreenCollection worldScreenCollection)
        {
            _parentForm            = parent;
            _worldScreenCollection = worldScreenCollection;

            InitalizeData();
        }
Пример #2
0
        private void item2ToolStripMenuItem_Click(object sender, EventArgs e)
        {
            DataViewForm dvf = new DataViewForm();

            dvf.PackName = (sender as ToolStripMenuItem).Tag.ToString();
            dvf.Show();
        }
Пример #3
0
        private void ShowNewForm(object sender, EventArgs e)
        {
            string databaseName = string.Empty;
            string sqlString    = string.Empty;

            // select
            using (var frm = new FolderBrowserDialog())
            {
                if (frm.ShowDialog() != DialogResult.OK)
                {
                    return;
                }
                databaseName = frm.SelectedPath;
            }

            // get SQL
            using (var sqlForm = new InputMultyLineForm())
            {
                if (sqlForm.ShowDialog() != DialogResult.OK)
                {
                    return;
                }

                sqlString = sqlForm.sqlTextBox.Text;
            }

            var chldForm = new DataViewForm()
            {
                MdiParent = this,
            };

            chldForm.SetSql(databaseName, sqlString);
            chldForm.Show();
        }
Пример #4
0
        private void OpenFile(object sender, EventArgs e)
        {
            OpenFileDialog openFileDialog = new OpenFileDialog();

            openFileDialog.InitialDirectory = Environment.GetFolderPath(Environment.SpecialFolder.Personal);
            openFileDialog.Filter           = "Файлы DBF (*.dbf)|*.dbf|Все файлы (*.*)|*.*";
            if (openFileDialog.ShowDialog(this) == DialogResult.OK)
            {
                var frm = new DataViewForm()
                {
                    MdiParent = this
                };
                frm.SetFiedName(openFileDialog.FileName);
                frm.Show();
            }
        }