Пример #1
0
        public byte[] uploadPic(int userID, string fileName)
        {
            FileStream fs     = new FileStream(fileName, FileMode.Open, FileAccess.Read);
            int        imgLen = (int)fs.Length;

            byte[] B = new byte[imgLen + 1];
            fs.Read(B, 0, imgLen);
            fs.Dispose();
            user.uploadPic(userID, B);
            return(B);
        }