/// <summary>
/// Generates a date adjusted to the user's timezone. Returns empty string if the date is not valid.
/// </summary>
/// <param name="xmldatetime">The date time in XML/ISO8601 as a string. In SQL, use this: CONVERT(varchar(24), [Column], 126)</param>
/// <param name="dateFormat">The output date format.</param>
/// <param name="user">The current user.</param>
public static string AdjustAndDisplayDate(DateTime date, ConversionDateFormatType dateFormat, UserInfo user)
{
if (date == DateTime.MinValue)
{
return(String.Empty);
}
return(Conversion.TranslateDate(AdjustDateTime(date, false, user), System.Threading.Thread.CurrentThread.CurrentCulture.TwoLetterISOLanguageName, dateFormat));
}
/// <summary>
/// Returns the date string in proper format, respective of the language.
/// </summary>
/// <param name="dt">The date to output.</param>
/// <param name="langcode">The current language ID.</param>
/// <param name="dateformat">Specifies how to format the returned date string.</param>
/// <param name="addtz">Whether or not to add timezone information to the end of the date string.</param>
public static string TranslateDate(this DateTime dt, string langcode, ConversionDateFormatType dateformat, bool addtz)
{
string dateformatstr;
//Return empty string if the DateTime is the min value
if (dt == DateTime.MinValue)
{
return("");
}
switch (dateformat)
{
case ConversionDateFormatType.FullDateTime:
dateformatstr = "dddd, MMMM dd, yyyy h:mm tt"; //6/15/2009 1:45:30 PM -> Monday, June 15, 2009 1:45 PM (en-US)
break;
case ConversionDateFormatType.LongDate:
dateformatstr = "dddd, MMMM dd, yyyy"; //6/15/2009 1:45:30 PM -> Monday, June 15, 2009 (en-US)
break;
case ConversionDateFormatType.ShortDate:
dateformatstr = "MM/dd/yyyy"; //6/15/2009 1:45:30 PM -> 6/15/2009 (en-US)
break;
case ConversionDateFormatType.MonthName:
dateformatstr = "MMMM"; //6/15/2009 1:45:30 PM -> June
break;
case ConversionDateFormatType.ShortMonthName:
dateformatstr = "MMM"; //6/15/2009 1:45:30 PM -> Jun
break;
case ConversionDateFormatType.ShortTime:
dateformatstr = "h:mm tt"; //6/15/2009 1:45:30 PM -> 1:45 PM
break;
case ConversionDateFormatType.LongTime:
dateformatstr = "h:mm:ss tt"; //6/15/2009 1:45:30 PM -> 1:45:30 PM
break;
default:
dateformatstr = "MM/dd/yyyy h:mm tt"; //6/15/2009 1:45:30 PM -> 6/15/2009 1:45 PM (en-US)
break;
}
return(dt.ToString(dateformatstr, CultureInfo.CreateSpecificCulture(langcode)) + (addtz ? " EST (GMT -5:00)" : ""));
}
/// <summary>
/// Generates a date adjusted to the user's timezone. Returns empty string if the date is not valid.
/// </summary>
/// <param name="xmldatetime">The date time in XML/ISO8601 as a string. In SQL, use this: CONVERT(varchar(24), [Column], 126)</param>
/// <param name="dateFormat">The output date format.</param>
/// <param name="user">The current user.</param>
public static string AdjustAndDisplayDate(string xmldatetime, ConversionDateFormatType dateFormat, UserInfo user)
{
return(AdjustAndDisplayDate(Conversion.XMLDateToDateTime(xmldatetime), dateFormat, user));
}
/// <summary>
/// Returns the date string in proper format, respective of the language.
/// </summary>
/// <param name="datestring">The date in XML date string (ISO 8601) format.</param>
/// <param name="langcode">The current language ID.</param>
/// <param name="dateformat">Specifies how to format the returned date string.</param>
/// <param name="addtz">Whether or not to add timezone information to the end of the date string.</param>
public static string TranslateDate(this string datestring, string langcode, ConversionDateFormatType dateformat, bool addtz)
{
return(TranslateDate(XMLDateToDateTime(datestring), langcode, dateformat, addtz));
}
/// <summary>
/// Returns the date string in proper format, respective of the language.
/// </summary>
/// <param name="datestring">The date in XML date string (ISO 8601) format.</param>
/// <param name="langcode">The current language ID.</param>
/// <param name="dateformat">Specifies how to format the returned date string.</param>
public static string TranslateDate(this string datestring, string langcode, ConversionDateFormatType dateformat)
{
return(TranslateDate(datestring, langcode, dateformat, false));
}
/// <summary>
/// Returns the date string in proper format, respective of the language.
/// </summary>
/// <param name="dt">The date to output.</param>
/// <param name="langcode">The current language ID.</param>
/// <param name="dateFormatType">Specifies how to format the returned date string.</param>
public static string TranslateDate(this DateTime dt, string langcode, ConversionDateFormatType dateFormatType)
{
return(TranslateDate(dt, langcode, dateFormatType, false));
}