int k = 0;//用于自增后读出print里的数据
internal void exchange(EdgesCollection edge)
{
int r = map.Node.Nodes.Count;//输入点数R
double[] a = new double[(r + 1) * (r + 1)];
for (int i = 0; i < r; i++)
{
for (int j = i + 1; j < r; j++)
{
MessageBox.Show(edge[k].Snode.Name + "到" + edge[k].Enode.Name + "的距离是：" + edge[k].Svalue);
a[i * r + j] = edge[k].Svalue;
if (k < r * (r - 1) / 2)
{
k++;
}
}
}
//----完善距离矩阵(距离矩阵其实可以是个上三角矩阵，
//----但为了处理方便，还是将其完整成一个对称阵)-----------
for (int i = 0; i < r; i++)
{
for (int j = 0; j < r; j++)
{
if (i == j)
{
a[i * r + j] = 0;
}
a[j * r + i] = a[i * r + j];
}
if (i == r - 1)
{
Marx m = new Marx(r, a);
string outs = "";
m.Find_way();
m.Display(ref outs, comEnd.Text, map.Node.Nodes);
txtOutroute.Text = outs;
}
}
}
internal void exchange(EdgesCollection edge)
{
int r = map.Node.Nodes.Count;//输入点数R
double[] a=new double[(r + 1) * (r + 1)];
for (int i = 0; i < r; i++)
{
for (int j = i + 1; j < r; j++)
{
MessageBox.Show(edge[k].Snode.Name + "到" + edge[k].Enode.Name + "的距离是：" + edge[k].Svalue);
a[i * r + j] = edge[k].Svalue;
if (k < r * (r - 1) / 2)
{
k++;
}
}
}
//----完善距离矩阵(距离矩阵其实可以是个上三角矩阵，
//----但为了处理方便，还是将其完整成一个对称阵)-----------
for (int i = 0; i < r; i++)
{
for (int j = 0; j < r; j++)
{
if (i == j)
{
a[i * r + j] = 0;
}
a[j * r + i] = a[i * r + j];
}
if (i == r - 1)
{
Marx m = new Marx(r, a);
string outs="";
m.Find_way();
m.Display(ref outs, comEnd.Text, map.Node.Nodes);
txtOutroute.Text = outs;
}
}
}