Withdraw() public method

public Withdraw ( decimal amount ) : bool
amount decimal
return bool
        static void Main()
        {
            IBankAccount venusAccount = new SaverAccount();
            IBankAccount jupiterAccount = new GoldAccount();

            venusAccount.PayIn(200);
            venusAccount.Withdraw(100);
            WriteLine(venusAccount.ToString());

            jupiterAccount.PayIn(500);
            jupiterAccount.Withdraw(600);
            jupiterAccount.Withdraw(100);
            WriteLine(jupiterAccount.ToString());
        }
Exemplo n.º 2
0
        static void Main()
        {
            IBankAccount venusAccount = new SaverAccount(); //using default constructor, balance is 0
             IBankAccount jupiterAccount = new GoldAccount();
             /*����instance from a interface instead of class���ĺô�����Inversion Of Control(���Ʒ�ת):
              * object is typically not known at compile time. you can call only methods that are part of
              * this interface through these references �� if you want to call any methods implemented by
              * a class that are not part of the interface, you need to cast the reference to the appropriate type.
              * But in the example code, you were able to call ToString() (not implemented by IBankAccount) without
              * any explicit cast, purely because ToString() is a System.Object method, so the C# compiler knows
              * that it will be supported by any class.*/
             venusAccount.PayIn(200);
             venusAccount.Withdraw(100);
             Console.WriteLine(venusAccount.ToString()); //override ToString
             jupiterAccount.PayIn(500);
             jupiterAccount.Withdraw(600); //withdraw attempt failed
             jupiterAccount.Withdraw(100);
             Console.WriteLine(jupiterAccount.ToString());

             //Interface references can in all respects be treated as class references �� but the power of an interface reference is that it can refer to any class that implements that interface.
        }