Exemplo n.º 1
0
 public ModuleNode(string projectName, string componentName, IEnumerable <SyntaxTreeNode> nodes, bool isClassModule)
     : base(Instruction.Empty(new LogicalCodeLine(projectName, componentName, 0, 0, string.Empty)), projectName, null, nodes)
 {
     _isClassModule = isClassModule;
     _projectName   = projectName;
     _componentName = componentName;
 }
Exemplo n.º 2
0
        /// <summary>
        /// Splits a logical code line into a number of <see cref="Instruction"/> instances.
        /// </summary>
        /// <returns></returns>
        public IEnumerable <Instruction> SplitInstructions()
        {
            // return empty instruction for empty line to preserve vertical whitespace:
            if (string.IsNullOrWhiteSpace(_content))
            {
                return(new[] { Instruction.Empty(this) });
            }

            const char separator = ':';

            // LabelSyntax uses instruction separator;
            // return entire line if there's no separator or if LabelSyntax matches:
            var stripped = _content.StripTrailingComment()
                           .StripStringLiterals();

            if (!stripped.Contains(separator) || Regex.Match(stripped, VBAGrammar.LabelSyntax).Success)
            {
                var indentation = stripped.TakeWhile(char.IsWhiteSpace).Count() + 1;
                return(new[] { new Instruction(this, indentation, stripped.Length, _content) });
            }

            var result            = new List <Instruction>();
            var instructionsCount = stripped.Count(c => c == separator) + 1;
            var startIndex        = 0;
            var endIndex          = 0;

            for (var instruction = 0; instruction < instructionsCount; instruction++)
            {
                endIndex = instruction == instructionsCount - 1
                    ? _content.Length
                    : _content.StripStringLiterals().IndexOf(separator, endIndex) + 1; // +1 because VBE index is 1-based, +1 because there's always a space after a ":".

                result.Add(new Instruction(this, startIndex, endIndex, _content.Substring(startIndex, endIndex - startIndex)));
                startIndex = endIndex;
            }

            return(result);
        }
Exemplo n.º 3
0
 public ProjectNode(string projectName, IEnumerable <SyntaxTreeNode> nodes)
     : base(Instruction.Empty(new LogicalCodeLine(projectName, projectName, 0, 0, string.Empty)), string.Empty, null, nodes)
 {
 }