private void CreateEdge(PapyrusControlFlowNode fromNode, PapyrusControlFlowNode toNode)
        {
            var edge = new PapyrusControlFlowEdge(fromNode, toNode);

            fromNode.Outgoing.Add(edge);
            toNode.Incoming.Add(edge);
        }
 public PapyrusControlFlowGraphBuilder(PapyrusMethodDefinition method)
 {
     this.method = method;
     entryPoint  = new PapyrusControlFlowNode(0, 0, PapyrusControlFlowNodeType.EntryPoint);
     nodes.Add(entryPoint);
     regularExit = new PapyrusControlFlowNode(1, -1, PapyrusControlFlowNodeType.RegularExit);
     nodes.Add(regularExit);
 }
Exemplo n.º 3
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        /// <summary>
        ///     Gets whether <c>this</c> dominates <paramref name="node" />.
        /// </summary>
        public bool Dominates(PapyrusControlFlowNode node)
        {
            // TODO: this can be made O(1) by numbering the dominator tree
            var tmp = node;

            while (tmp != null)
            {
                if (tmp == this)
                {
                    return(true);
                }
                tmp = tmp.ImmediateDominator;
            }
            return(false);
        }
Exemplo n.º 4
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        private static PapyrusControlFlowNode FindCommonDominator(PapyrusControlFlowNode b1, PapyrusControlFlowNode b2)
        {
            // Here we could use the postorder numbers to get rid of the hashset, see "A Simple, Fast Dominance Algorithm"
            var path1 = new HashSet <PapyrusControlFlowNode>();

            while (b1 != null && path1.Add(b1))
            {
                b1 = b1.ImmediateDominator;
            }
            while (b2 != null)
            {
                if (path1.Contains(b2))
                {
                    return(b2);
                }
                b2 = b2.ImmediateDominator;
            }
            throw new Exception("No common dominator found!");
        }
 private void CreateEdge(PapyrusControlFlowNode fromNode, PapyrusInstruction toInstruction)
 {
     CreateEdge(fromNode, nodes.Single(n => n.Start == toInstruction));
 }