Exemplo n.º 1
0
        public bool Intersects(DoubleLineSegment2 other)
        {
            double ax = X1, ay = Y1, bx = X2, by = Y2;
            double cx = other.X1, cy = other.Y1, dx = other.X2, dy = other.Y2;

            return(Intersects(ax, ay, bx, by, cx, cy, dx, dy));
        }
Exemplo n.º 2
0
        public static int Compare(DoubleVector2 p, DoubleLineSegment2 a, DoubleLineSegment2 b)
        {
            // TODO: Why did I comment this
//#if DEBUG
//         if (GeometryOperations.Clockness(p.X, p.Y, a.X1, a.Y1, a.X2, a.Y2) != Clockness.Clockwise) {
//            throw new InvalidStateException();
//         }
//         if (GeometryOperations.Clockness(p.X, p.Y, b.X1, b.Y1, b.X2, b.Y2) != Clockness.Clockwise) {
//            throw new InvalidStateException();
//         }
//#endif
            var clk = GeometryOperations.Clockness(p.X, p.Y, a.X1, a.Y1, b.X1, b.Y1);

            if (clk != Clockness.Clockwise)
            {
                // b before a; b \' a *origin
                var res = (int)GeometryOperations.Clockness(b.First, b.Second, a.First);
                if (res != 0)
                {
                    return(res);
                }

                // just need something to resolve ambiguity. b1 b2 a1 is collinear.
                // a1 must be within the angle b1 p b2 (see visibility polygon building algorithm)
                // so a1 is BETWEEN b1 b2. a2 cannot be collinear with b1 b2 (disallow segments intersecting
                // other than at endpoint), but still, a2 is either 'in front of' or 'behind' b.
                res = (int)GeometryOperations.Clockness(b.First, b.Second, a.Second);
#if DEBUG
                if (res == 0 && a != b)
                {
                    throw new BadInputException();
                }
#endif
                return(res);
            }
            else
            {
                // a before b; a \' b *origin
                var res = -(int)GeometryOperations.Clockness(a.First, a.Second, b.First);
                if (res != 0)
                {
                    return(res);
                }

                // just need something to resolve ambiguity. a1 a2 b1 is collinear.
                res = -(int)GeometryOperations.Clockness(a.First, a.Second, b.Second);
#if DEBUG
                if (res == 0 && a != b)
                {
                    throw new BadInputException();
                }
#endif
                return(res);
            }
        }
Exemplo n.º 3
0
        // assumes p is ccw ordered, edge is counted as interior (neither case)
        public static bool SegmentIntersectsNonDegenerateConvexPolygonInterior(DoubleLineSegment2 s, DoubleVector2[] p)
        {
#if DEBUG
            if (Clockness(p[0], p[1], p[2]) == Clk.Clockwise)
            {
                throw new BadInputException("p not ccw");
            }
            if (p.Length < 3)
            {
                throw new BadInputException("len(p) < 3");
            }
#endif
            var(x, y) = s;
            bool          xInterior = true, yInterior = true;
            DoubleVector2 a = p[p.Length - 1], b;
            int           i = 0;
            for (; i < p.Length && (xInterior || yInterior); i++, a = b)
            {
                b = p[i];
                var abx = Clockness(a, b, x);
                var aby = Clockness(a, b, y);
                if (abx == Clk.Clockwise && aby == Clk.Clockwise)
                {
                    return(false);
                }
                xInterior &= abx != Clk.Clockwise;
                yInterior &= aby != Clk.Clockwise;
                if (abx == (Clk)(-(int)aby) || abx == Clk.Neither || aby == Clk.Neither)
                {
                    // The below is equivalent to:
                    // // (a, b) places x, y onto opposite half-planes.
                    // // Intersect if (x, y) places a, b onto opposite half-planes.
                    // var xya = Clockness(x, y, a);
                    // var xyb = Clockness(x, y, b);
                    // if (xya != xyb || xya == Clk.Neither || xyb == Clk.Neither) return true;
                    if (DoubleLineSegment2.Intersects(a.X, a.Y, b.X, b.Y, x.X, x.Y, y.X, y.Y))
                    {
                        return(true);
                    }
                }
            }
            for (; i < p.Length; i++, a = b)
            {
                b = p[i];
                if (DoubleLineSegment2.Intersects(a.X, a.Y, b.X, b.Y, x.X, x.Y, y.X, y.Y))
                {
                    return(true);
                }
            }
            return(xInterior && yInterior);
        }
Exemplo n.º 4
0
 public static bool SegmentIntersectsConvexPolygonInterior(DoubleLineSegment2 s, DoubleVector2[] p)
 {
     if (p.Length == 1)
     {
         return(false);
     }
     else if (p.Length == 2)
     {
         return(s.Intersects(new DoubleLineSegment2(p[0], p[1])));
     }
     else
     {
         return(SegmentIntersectsNonDegenerateConvexPolygonInterior(s, p));
     }
 }
Exemplo n.º 5
0
 public static DoubleVector2 FindNearestPoint(DoubleLineSegment2 segment, DoubleVector2 query)
 {
     return(FindNearestPoint(segment.First, segment.Second, query));
 }
Exemplo n.º 6
0
 // NOTE: Assumes lines are valid (two distinct endpoints) NOT line-OVERLAPPING
 // that is, lines should not have more than 1 point of intersection.
 // if lines DO have more than 1 point of intersection, this returns no intersection found.
 public static bool TryFindNonoverlappingLineLineIntersectionT(ref DoubleLineSegment2 a, ref DoubleLineSegment2 b, out double tForA)
 {
     return(TryFindNonoverlappingLineLineIntersectionT(a.First, a.Second, b.First, b.Second, out tForA));
 }
Exemplo n.º 7
0
 // Equality by endpoints, not line geometry
 public bool Equals(DoubleLineSegment2 other)
 {
     return(First == other.First && Second == other.Second);
 }