public MyList()
{
headNode = null;
}
public MyNode(int i)
{
data = i;
next = null;
}
static bool listIsBiPartitite(MyList[] array, int n)
{
int i = 0;
// This is an array to define the set of each node:
// D means Domain
// R means Range
// N means Not defined
char[] sets = new char[n];
//initialize the nodes with 'N' Not definied
for (int m = 1; m < n; m++)
{
sets[m] = 'N';
}
sets[0] = 'D'; //Suppose that the first node is in the domain set
while (i < n)
{
MyNode tmp = array[i].headNode; //tmp node to scan the set
int headNumber = array[i].headNode.data - 1; //Getting the number of the first node of the list
if (tmp != null)
{
tmp = tmp.next;
while (tmp != null)
{
if (sets[headNumber] == 'N') //If the headnode is not in any set we check the set of the other nodes that have connections with it
{
while (tmp != null)
{
if (sets[tmp.data - 1] != 'N')
//If one of the connections is already in a set then assign the headnode to the opposite set
{
if (sets[tmp.data - 1] == 'D')
{
sets[headNumber] = 'R';
}
else
{
sets[headNumber] = 'D';
}
tmp = array[i].headNode; //Go back to the beginning of the list to check the previous unassigned nodes
break;
}
tmp = tmp.next;
}
if (tmp == null) //If none of the nodes is assigned then assign the headnode to an arbitary set
{
sets[headNumber] = 'D';
tmp = array[i].headNode;
}
}
else if (sets[headNumber] == sets[tmp.data - 1]) // If two nodes that are connected with each other belong to the same set
{
return(false); //Then the graph is not Bipartite
}
//Else assign all the nodes connected to the headnode to the opposite set of the headnode
else if (sets[headNumber] == 'D')
{
sets[tmp.data - 1] = 'R';
}
else
{
sets[tmp.data - 1] = 'D';
}
tmp = tmp.next;
}
}
i++;
}
return(true);
}