public string ToDegreesString()
{
var s2LatLng = new S2LatLng(this);
return("(" + s2LatLng.LatDegrees + ", "
+ s2LatLng.LngDegrees + ")");
}
/**
* Return the center of the rectangle in latitude-longitude space (in general
* this is not the center of the region on the sphere).
*/
/**
* Return the minimum distance (measured along the surface of the sphere)
* from a given point to the rectangle (both its boundary and its interior).
* The latLng must be valid.
*/
public S1Angle GetDistance(S2LatLng p)
{
// The algorithm here is the same as in getDistance(S2LagLngRect), only
// with simplified calculations.
var a = this;
Preconditions.CheckState(!a.IsEmpty);
Preconditions.CheckArgument(p.IsValid);
if (a.Lng.Contains(p.Lng.Radians))
{
return(S1Angle.FromRadians(Math.Max(0.0, Math.Max(p.Lat.Radians - a.Lat.Hi,
a.Lat.Lo - p.Lat.Radians))));
}
var interval = new S1Interval(a.Lng.Hi, a.Lng.Complement.Center);
var aLng = a.Lng.Lo;
if (interval.Contains(p.Lng.Radians))
{
aLng = a.Lng.Hi;
}
var lo = S2LatLng.FromRadians(a.Lat.Lo, aLng).ToPoint();
var hi = S2LatLng.FromRadians(a.Lat.Hi, aLng).ToPoint();
var loCrossHi =
S2LatLng.FromRadians(0, aLng - S2.PiOver2).Normalized.ToPoint();
return(S2EdgeUtil.GetDistance(p.ToPoint(), lo, hi, loCrossHi));
}
/**
* Returns true if the edge (v0, v1) intersects the given longitude
* interval, and then saves 'v1' to be used as the next 'v0'.
*/
public bool Intersects(S2Point v1)
{
var lng1 = S2LatLng.Longitude(v1).Radians;
var result = interval.Intersects(S1Interval.FromPointPair(lng0, lng1));
lng0 = lng1;
return(result);
}
// Increase the size of the bounding rectangle to include the given point.
// The rectangle is expanded by the minimum amount possible.
public S2LatLngRect AddPoint(S2LatLng ll)
{
// assert (ll.isValid());
var newLat = _lat.AddPoint(ll.Lat.Radians);
var newLng = _lng.AddPoint(ll.Lng.Radians);
return(new S2LatLngRect(newLat, newLng));
}
/**
* Return true if the edge AB intersects the given edge of constant longitude.
*/
private static bool IntersectsLngEdge(S2Point a, S2Point b,
R1Interval lat, double lng)
{
// Return true if the segment AB intersects the given edge of constant
// longitude. The nice thing about edges of constant longitude is that
// they are straight lines on the sphere (geodesics).
return(S2.SimpleCrossing(a, b, S2LatLng.FromRadians(lat.Lo, lng)
.ToPoint(), S2LatLng.FromRadians(lat.Hi, lng).ToPoint()));
}
/**
* Return a rectangle that contains all points whose latitude distance from
* this rectangle is at most margin.Lat, and whose longitude distance from
* this rectangle is at most margin.Lng. In particular, latitudes are
* clamped while longitudes are wrapped. Note that any expansion of an empty
* interval remains empty, and both components of the given margin must be
* non-negative.
*
* NOTE: If you are trying to grow a rectangle by a certain *distance* on the
* sphere (e.g. 5km), use the ConvolveWithCap() method instead.
*/
public S2LatLngRect Expanded(S2LatLng margin)
{
// assert (margin.Lat.radians() >= 0 && margin.Lng.radians() >= 0);
if (IsEmpty)
{
return(this);
}
return(new S2LatLngRect(_lat.Expanded(margin.Lat.Radians).Intersection(
FullLat), _lng.Expanded(margin.Lng.Radians)));
}
public void AddPoint(S2Point b)
{
// assert (S2.isUnitLength(b));
var bLatLng = new S2LatLng(b);
if (bound.IsEmpty)
{
bound = bound.AddPoint(bLatLng);
}
else
{
// We can't just call bound.addPoint(bLatLng) here, since we need to
// ensure that all the longitudes between "a" and "b" are included.
bound = bound.Union(S2LatLngRect.FromPointPair(aLatLng, bLatLng));
// Check whether the Min/Max latitude occurs in the edge interior.
// We find the normal to the plane containing AB, and then a vector
// "dir" in this plane that also passes through the equator. We use
// RobustCrossProd to ensure that the edge normal is accurate even
// when the two points are very close together.
var aCrossB = S2.RobustCrossProd(a, b);
var dir = S2Point.CrossProd(aCrossB, new S2Point(0, 0, 1));
var da = dir.DotProd(a);
var db = dir.DotProd(b);
if (da * db < 0)
{
// Minimum/maximum latitude occurs in the edge interior. This affects
// the latitude bounds but not the longitude bounds.
var absLat = Math.Acos(Math.Abs(aCrossB[2] / aCrossB.Norm));
var lat = bound.Lat;
if (da < 0)
{
// It's possible that absLat < lat.lo() due to numerical errors.
lat = new R1Interval(lat.Lo, Math.Max(absLat, bound.Lat.Hi));
}
else
{
lat = new R1Interval(Math.Min(-absLat, bound.Lat.Lo), lat.Hi);
}
bound = new S2LatLngRect(lat, bound.Lng);
}
}
a = b;
aLatLng = bLatLng;
}
/**
* Return true if the rectangle is valid, which essentially just means that
* the latitude bounds do not exceed Pi/2 in absolute value and the longitude
* bounds do not exceed Pi in absolute value.
*
*/
/** Return the k-th vertex of the rectangle (k = 0,1,2,3) in CCW order. */
public S2LatLng GetVertex(int k)
{
// Return the points in CCW order (SW, SE, NE, NW).
switch (k)
{
case 0:
return(S2LatLng.FromRadians(_lat.Lo, _lng.Lo));
case 1:
return(S2LatLng.FromRadians(_lat.Lo, _lng.Hi));
case 2:
return(S2LatLng.FromRadians(_lat.Hi, _lng.Hi));
case 3:
return(S2LatLng.FromRadians(_lat.Hi, _lng.Lo));
default:
throw new ArgumentException("Invalid vertex index.");
}
}
/**
* Return the minimum distance (measured along the surface of the sphere) to
* the given S2LatLngRect. Both S2LatLngRects must be non-empty.
*/
public S1Angle GetDistance(S2LatLngRect other)
{
var a = this;
var b = other;
Preconditions.CheckState(!a.IsEmpty);
Preconditions.CheckArgument(!b.IsEmpty);
// First, handle the trivial cases where the longitude intervals overlap.
if (a.Lng.Intersects(b.Lng))
{
if (a.Lat.Intersects(b.Lat))
{
return(S1Angle.FromRadians(0)); // Intersection between a and b.
}
// We found an overlap in the longitude interval, but not in the latitude
// interval. This means the shortest path travels along some line of
// longitude connecting the high-latitude of the lower rect with the
// low-latitude of the higher rect.
S1Angle lo, hi;
if (a.Lat.Lo > b.Lat.Hi)
{
lo = b.LatHi;
hi = a.LatLo;
}
else
{
lo = a.LatHi;
hi = b.LatLo;
}
return(S1Angle.FromRadians(hi.Radians - lo.Radians));
}
// The longitude intervals don't overlap. In this case, the closest points
// occur somewhere on the pair of longitudinal edges which are nearest in
// longitude-space.
S1Angle aLng, bLng;
var loHi = S1Interval.FromPointPair(a.Lng.Lo, b.Lng.Hi);
var hiLo = S1Interval.FromPointPair(a.Lng.Hi, b.Lng.Lo);
if (loHi.Length < hiLo.Length)
{
aLng = a.LngLo;
bLng = b.LngHi;
}
else
{
aLng = a.LngHi;
bLng = b.LngLo;
}
// The shortest distance between the two longitudinal segments will include
// at least one segment endpoint. We could probably narrow this down further
// to a single point-edge distance by comparing the relative latitudes of the
// endpoints, but for the sake of clarity, we'll do all four point-edge
// distance tests.
var aLo = new S2LatLng(a.LatLo, aLng).ToPoint();
var aHi = new S2LatLng(a.LatHi, aLng).ToPoint();
var aLoCrossHi =
S2LatLng.FromRadians(0, aLng.Radians - S2.PiOver2).Normalized.ToPoint();
var bLo = new S2LatLng(b.LatLo, bLng).ToPoint();
var bHi = new S2LatLng(b.LatHi, bLng).ToPoint();
var bLoCrossHi =
S2LatLng.FromRadians(0, bLng.Radians - S2.PiOver2).Normalized.ToPoint();
return(S1Angle.Min(S2EdgeUtil.GetDistance(aLo, bLo, bHi, bLoCrossHi),
S1Angle.Min(S2EdgeUtil.GetDistance(aHi, bLo, bHi, bLoCrossHi),
S1Angle.Min(S2EdgeUtil.GetDistance(bLo, aLo, aHi, aLoCrossHi),
S2EdgeUtil.GetDistance(bHi, aLo, aHi, aLoCrossHi)))));
}
/**
*'interval' is the longitude interval to be tested against, and 'v0' is
* the first vertex of edge chain.
*/
public LongitudePruner(S1Interval interval, S2Point v0)
{
this.interval = interval;
lng0 = S2LatLng.Longitude(v0).Radians;
}
/**
* Returns true if this rectangle intersects the given cell. (This is an exact
* test and may be fairly expensive, see also MayIntersect below.)
*/
public bool Intersects(S2Cell cell)
{
// First we eliminate the cases where one region completely contains the
// other. Once these are disposed of, then the regions will intersect
// if and only if their boundaries intersect.
if (IsEmpty)
{
return(false);
}
if (Contains(cell.Center))
{
return(true);
}
if (cell.Contains(Center.ToPoint()))
{
return(true);
}
// Quick rejection test (not required for correctness).
if (!Intersects(cell.RectBound))
{
return(false);
}
// Now check whether the boundaries intersect. Unfortunately, a
// latitude-longitude rectangle does not have straight edges -- two edges
// are curved, and at least one of them is concave.
// Precompute the cell vertices as points and latitude-longitudes.
var cellV = new S2Point[4];
var cellLl = new S2LatLng[4];
for (var i = 0; i < 4; ++i)
{
cellV[i] = cell.GetVertex(i); // Must be normalized.
cellLl[i] = new S2LatLng(cellV[i]);
if (Contains(cellLl[i]))
{
return(true); // Quick acceptance test.
}
}
for (var i = 0; i < 4; ++i)
{
var edgeLng = S1Interval.FromPointPair(
cellLl[i].Lng.Radians, cellLl[(i + 1) & 3].Lng.Radians);
if (!_lng.Intersects(edgeLng))
{
continue;
}
var a = cellV[i];
var b = cellV[(i + 1) & 3];
if (edgeLng.Contains(_lng.Lo))
{
if (IntersectsLngEdge(a, b, _lat, _lng.Lo))
{
return(true);
}
}
if (edgeLng.Contains(_lng.Hi))
{
if (IntersectsLngEdge(a, b, _lat, _lng.Hi))
{
return(true);
}
}
if (IntersectsLatEdge(a, b, _lat.Lo, _lng))
{
return(true);
}
if (IntersectsLatEdge(a, b, _lat.Hi, _lng))
{
return(true);
}
}
return(false);
}
/**
* More efficient version of InteriorContains() that accepts a S2LatLng rather
* than an S2Point.
*/
public bool InteriorContains(S2LatLng ll)
{
// assert (ll.isValid());
return(_lat.InteriorContains(ll.Lat.Radians) && _lng
.InteriorContains(ll.Lng.Radians));
}
public S2Cell(S2LatLng ll)
{
Init(S2CellId.FromLatLng(ll));
}
/**
* Construct a rectangle from minimum and maximum latitudes and longitudes. If
* lo.Lng > hi.Lng, the rectangle spans the 180 degree longitude line.
*/
public S2LatLngRect(S2LatLng lo, S2LatLng hi)
{
_lat = new R1Interval(lo.Lat.Radians, hi.Lat.Radians);
_lng = new S1Interval(lo.Lng.Radians, hi.Lng.Radians);
// assert (isValid());
}
/**
* Convenience method to construct the minimal bounding rectangle containing
* the two given points. This is equivalent to starting with an empty
* rectangle and calling AddPoint() twice. Note that it is different than the
* S2LatLngRect(lo, hi) constructor, where the first point is always used as
* the lower-left corner of the resulting rectangle.
*/
public static S2LatLngRect FromPointPair(S2LatLng p1, S2LatLng p2)
{
// assert (p1.isValid() && p2.isValid());
return(new S2LatLngRect(R1Interval.FromPointPair(p1.Lat.Radians, p2.Lat.Radians), S1Interval.FromPointPair(p1.Lng.Radians, p2.Lng.Radians)));
}
/** Convenience method to construct a rectangle containing a single point. */
public static S2LatLngRect FromPoint(S2LatLng p)
{
// assert (p.isValid());
return(new S2LatLngRect(p, p));
}
/** The canonical empty rectangle */
/**
* Construct a rectangle from a center point (in lat-lng space) and size in
* each dimension. If size.Lng is greater than 360 degrees it is clamped,
* and latitudes greater than +/- 90 degrees are also clamped. So for example,
* FromCenterSize((80,170),(20,20)) -> (lo=(60,150),hi=(90,-170)).
*/
public static S2LatLngRect FromCenterSize(S2LatLng center, S2LatLng size)
{
return(FromPoint(center).Expanded(size * 0.5));
}
/** Return the leaf cell containing the given S2LatLng. */
public static S2CellId FromLatLng(S2LatLng ll)
{
return(FromPoint(ll.ToPoint()));
}
