Exemplo n.º 1
0
        /// <summary>
        /// Returns the distance that is appropriate for N dimensions.  In otherwords, if this point is
        /// three dimensional, then all three dimensions will be used for calculating the distance.
        /// </summary>
        /// <param name="coordinate">The coordinate to compare to this coordinate</param>
        /// <returns>A double valued distance measure that is invariant to the number of coordinates</returns>
        /// <exception cref="CoordinateMismatchException">The number of dimensions does not match between the points.</exception>
        public double HyperDistance(Coordinate coordinate)
        {
            if (coordinate.NumOrdinates != NumOrdinates)
            {
                throw new CoordinateMismatchException();
            }
            double sqrDist = 0;

            double[] vals = coordinate.ToArray();
            for (int i = 0; i < NumOrdinates; i++)
            {
                double diff = vals[i] - Coordinate[i];
                sqrDist += diff * diff;
            }
            return(Math.Sqrt(sqrDist));
        }
Exemplo n.º 2
0
        /// <summary>
        /// Returns the distance that is appropriate for N dimensions.  In otherwords, if this point is
        /// three dimensional, then all three dimensions will be used for calculating the distance.
        /// </summary>
        /// <param name="coordinate">The coordinate to compare to this coordinate</param>
        /// <returns>A double valued distance measure that is invariant to the number of coordinates</returns>
        /// <exception cref="CoordinateMismatchException">The number of dimensions does not match between the points.</exception>
        public double HyperDistance(Coordinate coordinate)
        {
            if (coordinate.NumOrdinates != NumOrdinates)
            {
                throw new CoordinateMismatchException();
            }
            double[] vals    = coordinate.ToArray();
            double   diff    = vals[0] - Convert.ToDouble(_x);
            double   sqrDist = diff * diff;

            diff     = vals[1] - Convert.ToDouble(_y);
            sqrDist += diff * diff;
            diff     = vals[2] - Convert.ToDouble(_z);
            sqrDist += diff * diff;

            return(Math.Sqrt(sqrDist));
        }
Exemplo n.º 3
0
 /// <summary>
 /// Creates an array of ordinate values that is the size of NumDimensions.  This
 /// will not include an M value.
 /// </summary>
 /// <returns>An Array of double values, with one value for each ordinate.</returns>
 public double[] ToArray()
 {
     return(Coordinate.ToArray());
 }