static void Main()
{
C obj = new C("ABC");
// StringSupplier f1 = () => obj.ToString(); // Anonymous method, Lambda
StringSupplier f2 = obj.ToString; // Method Reference <=> Java> obj::ToString
StringSupplier f3 = new StringSupplier(obj.ToString);
StringSupplier f4 = App.Foo; // ldnull + ldftn App:: Foo + newobj StringSupplier
Bar(obj.Equals); // ldloc0 + ldvirtftn C::Equals + newobj Predicate + call App::Bar
string s1 = f2.Invoke();
string s2 = f2(); // <=> f2.Invoke()
}
static void Main()
{
C obj = new C("ABC");
// StringSupplier f1 = App.Foo; // ldnull + ldftn App:: Foo + newobj StringSupplier
/**
* Is there any difference in IL from the compilation of f1 and f2 assignment?
* R: yes
* Which instruction is different?
* f1: ldftn App/'<>c__DisplayClass2_0'::'<Main>b__0' // anymous method containing the lambda body
* f2: ldvirtftn Object::ToString()
*/
StringSupplier f1 = () => obj.ToString(); // Anonymous method, Lambda
StringSupplier f2 = obj.ToString; // Method Reference <=> Java> obj::ToString
// f1() == f2() // f1() two jumps and f2() one jump
StringSupplier f3 = new StringSupplier(obj.ToString); // <=> f2
Bar(obj.Equals); // ldloc0 + dup + ldvirtftn C::Equals + newobj Predicate + call App::Bar
string s1 = f2.Invoke();
string s2 = f2(); // <=> f2.Invoke()
}
