private void AppWindow_InputActivationChanged(InputActivationListener sender, InputActivationListenerActivationChangedEventArgs args)
{
_windowActivated = args.State != InputActivationState.Deactivated;
UpdateBrush();
}
private void ActivationListener_InputActivationChanged(InputActivationListener sender, InputActivationListenerActivationChangedEventArgs args)
{
// Dummy method for now just to show the outline.
// This sample has no content that needs modification due to activation state.
// We are entirely relying on XAML to do the right thing for our simple app. :)
switch (args.State)
{
case InputActivationState.ActivatedInForeground:
// The user will be interacting with this window, so make sure the full user experience is running
break;
case InputActivationState.ActivatedNotForeground:
// The window is showing, but the user is interacting with another window, adjust accordingly
break;
case InputActivationState.Deactivated:
// The user moved on, they have switched to another window, time to go back to inactive state.
break;
default:
break;
}
}
