Exemplos de DialogUtil.ShowOpenFileDialog em C# (CSharp)

Exemplo n.º 1

        private async static void OnOpenXamlCommand(object sender, RoutedEventArgs e)
        {
            var fileName = DialogUtil.ShowOpenFileDialog("XAML|*.xaml");

            if (string.IsNullOrEmpty(fileName) || !File.Exists(fileName))
            {
                return;
            }

            var ctrl = sender as LiveXaml;

            using (var fs = new FileStream(fileName, FileMode.Open, FileAccess.Read))
            {
                using (var sr = new StreamReader(fs, Encoding.UTF8))
                {
                    ctrl.Text = await sr.ReadToEndAsync();
                }
            }
        }