// 懒人版，如果不想添加Request,Response,Model。可以用这种方式，返回Dictionary<string, object>，后续自己处理
private static void TestCommon()
{
// 创建请求对象
CommonRequest request = new CommonRequest("alipay.story.find");
// 请求参数
Dictionary <string, string> bizModel = new Dictionary <string, string>
{
["name"] = "白雪公主"
};
request.BizModel = bizModel;
// 发送请求
CommonResponse response = client.Execute(request);
if (response.IsSuccess())
{
// 返回结果
string body = response.Body;
Dictionary <string, object> dict = JsonUtil.ParseToDictionary(body);
Console.WriteLine("Dictionary内容:");
foreach (var item in dict)
{
Console.WriteLine("{0}:{1}", item.Key, item.Value);
}
}
else
{
Console.WriteLine("错误, code:{0}, msg:{1}, subCode:{2}, subMsg:{3}",
response.Code, response.Msg, response.SubCode, response.SubMsg);
}
}
public void TestLazy()
{
// 接口请求
CommonRequest request = new CommonRequest("goods.get");
// 请求参数
Dictionary <string, object> param = new Dictionary <string, object>();
// 属性赋值
param["goods_name"] = "iphone6";
// 设置请求参数
request.Param = param;
// 发送请求，返回结果
CommonResponse response = client.Execute <CommonResponse>(request);
if (response.IsSuccess())
{
Assert.IsTrue(response.data is Dictionary <string, object>);
Assert.IsTrue(response.data["goods_name"].ToString() == "苹果iPhoneX");
}
else
{
throw new SystemException(response.msg);
}
}