Exemplo n.º 1
0
    public void Pathfind_StartOutOfMatrix_2()
    {
        AStarWithMinBinary aStar = new AStarWithMinBinary(7, 7);

        Vector2 startPosition = new Vector2(0, -1);
        Vector2 endPosition   = new Vector2(6, 6);

        aStar.FindPath(startPosition, endPosition);

        foreach (AStarWithMinBinaryHeapNode node in aStar.matrix)
        {
            Assert.AreEqual(null, node.nextNode);
        }
    }
Exemplo n.º 2
0
    public void Pathfind_EndIsObstacle()
    {
        AStarWithMinBinary aStar = new AStarWithMinBinary(7, 7);

        Vector2 startPosition = new Vector2(0, 0);
        Vector2 endPosition   = new Vector2(6, 6);

        aStar.SetObstacle(new Vector2(6, 6));

        aStar.FindPath(startPosition, endPosition);

        foreach (AStarWithMinBinaryHeapNode node in aStar.matrix)
        {
            Assert.AreEqual(null, node.nextNode);
        }
    }
Exemplo n.º 3
0
    public void Pathfind_CanFind_NoObstacle()
    {
        AStarWithMinBinary aStar = new AStarWithMinBinary(7, 7);

        Vector2 startPosition = new Vector2(0, 0);
        Vector2 endPosition   = new Vector2(6, 6);

        aStar.FindPath(startPosition, endPosition);

        /*
         *  ↓   ←   ←   ←   ←   ←   E
         *
         *  ↓   ←   ↑   ↑   ↑   ↑   0
         *
         *  ↓   ←   0   0   0   0   0
         *
         *  ↓   ←   0   0   0   0   0
         *
         *  ↓   ←   0   0   0   0   0
         *
         *  ↓   ←   0   0   0   0   0
         *
         *  S   ←   0   0   0   0   0
         */
        AStarWithMinBinaryHeapNode[,] matrix    = aStar.matrix;
        AStarWithMinBinaryHeapNode[,] nextNodes = new AStarWithMinBinaryHeapNode[7, 7]
        {
            { null, matrix[0, 0], null, null, null, null, null },
            { matrix[0, 0], matrix[0, 1], null, null, null, null, null },
            { matrix[0, 1], matrix[0, 2], null, null, null, null, null },
            { matrix[0, 2], matrix[0, 3], null, null, null, null, null },
            { matrix[0, 3], matrix[0, 4], null, null, null, null, null },
            { matrix[0, 4], matrix[0, 5], matrix[2, 6], matrix[3, 6], matrix[4, 6], matrix[5, 6], null },
            { matrix[0, 5], matrix[0, 6], matrix[1, 6], matrix[2, 6], matrix[3, 6], matrix[4, 6], matrix[5, 6] }
        };
        for (int x = 0; x < 7; x++)
        {
            for (int y = 0; y < 7; y++)
            {
                Assert.AreEqual(nextNodes[y, x], aStar.matrix[x, y].nextNode);      //二维数组赋值是按照横竖x的方式进行的,也就是说上面的矩阵写错了,要转置,这就是一个用 [y, x] 一个用 [x, y] 的原因
            }
        }
    }
Exemplo n.º 4
0
    public void SetObstacle_Normal()
    {
        Vector2 obstaclePosition = new Vector2(5, 3);

        AStarWithMinBinary aStar = new AStarWithMinBinary(10, 10);

        aStar.SetObstacle(obstaclePosition);

        for (int x = 0; x < aStar.matrix.GetLength(0); x++)
        {
            for (int y = 0; y < aStar.matrix.GetLength(1); y++)
            {
                if (x != (int)obstaclePosition.x || y != (int)obstaclePosition.y)
                {
                    Assert.IsTrue(aStar.matrix[x, y].canThrough);
                }
                else
                {
                    Assert.IsFalse(aStar.matrix[x, y].canThrough);
                }
            }
        }
    }
 void CreatAStar()
 {
     _aStar = new AStarWithMinBinary(_width, _height);
 }