//very similar to parent(), but assumes contextRef refers to a singular, existing node in the model
//this means we can do '/a/b/c + ../../d/e/f = /a/d/e/f', which we couldn't do in parent()
//return null if context ref is not absolute, or we parent up past the root node
//NOTE: this function still works even when contextRef contains INDEX_UNBOUND multiplicites... conditions depend on this behavior,
// even though it's slightly icky
public TreeReference anchor(TreeReference contextRef)
{
if (isAbsolute())
{
return(this.clone());
}
else if (!contextRef.isAbsolute())
{
return(null);
}
else
{
TreeReference newRef = contextRef.clone();
int contextSize = contextRef.size();
if (refLevel > contextSize)
{
return(null); //tried to do '/..'
}
else
{
for (int i = 0; i < refLevel; i++)
{
newRef.removeLastLevel();
}
for (int i = 0; i < size(); i++)
{
newRef.add(this.getName(i), this.getMultiplicity(i));
}
return(newRef);
}
}
}
/// <summary>Intersect this tree reference with another, returning a new tree reference
/// which contains all of the common elements, starting with the root element.
///
/// Note that relative references by their nature can't share steps, so intersecting
/// any (or by any) relative ref will result in the root ref. Additionally, if the
/// two references don't share any steps, the intersection will consist of the root
/// reference.
///
/// </summary>
/// <param name="b">The tree reference to intersect
/// </param>
/// <returns> The tree reference containing the common basis of this ref and b
/// </returns>
public virtual TreeReference intersect(TreeReference b)
{
if (!this.Absolute || !b.Absolute)
{
return(TreeReference.rootRef());
}
if (this.Equals(b))
{
return(this);
}
TreeReference a;
//A should always be bigger if one ref is larger than the other
if (this.size() < b.size())
{
a = b.Clone(); b = this.Clone();
}
else
{
a = this.Clone(); b = b.Clone();
}
//Now, trim the refs to the same length.
int diff = a.size() - b.size();
for (int i = 0; i < diff; ++i)
{
a.removeLastLevel();
}
int aSize = a.size();
//easy, but requires a lot of re-evaluation.
for (int i = 0; i <= aSize; ++i)
{
if (a.Equals(b))
{
return(a);
}
else if (a.size() == 0)
{
return(TreeReference.rootRef());
}
else
{
if (!a.removeLastLevel() || !b.removeLastLevel())
{
//I don't think it should be possible for us to get here, so flip if we do
throw new System.SystemException("Dug too deply into TreeReference during intersection");
}
}
}
//The only way to get here is if a's size is -1
throw new System.SystemException("Impossible state");
}
public TreeReference getParentRef()
{
//TODO: level
TreeReference ref_ = this.clone();
if (ref_.removeLastLevel())
{
return(ref_);
}
else
{
return(null);
}
}
//very similar to parent(), but assumes contextRef refers to a singular, existing node in the model
//this means we can do '/a/b/c + ../../d/e/f = /a/d/e/f', which we couldn't do in parent()
//return null if context ref is not absolute, or we parent up past the root node
//NOTE: this function still works even when contextRef contains INDEX_UNBOUND multiplicites... conditions depend on this behavior,
// even though it's slightly icky
public virtual TreeReference anchor(TreeReference contextRef)
{
//TODO: Technically we should possibly be modifying context stuff here
//instead of in the xpath stuff;
if (Absolute)
{
return(this.Clone());
}
else if (!contextRef.Absolute)
{
throw new XPathException("Could not resolve " + this.toString(true));
}
else
{
TreeReference newRef = contextRef.Clone();
int contextSize = contextRef.size();
if (refLevel > contextSize)
{
//tried to do '/..'
throw new XPathException("Could not resolve " + this.toString(true));
}
else
{
for (int i = 0; i < refLevel; i++)
{
newRef.removeLastLevel();
}
for (int i = 0; i < size(); i++)
{
newRef.add(data.elementAt(i).shallowCopy());
}
return(newRef);
}
}
}
