public LandPriceInfoTree()
{
root = null;
_count = 0;
}
// Recursive destruction of binary search tree, called by method clear
// and destroy. Can be used to kill a sub-tree of a larger tree.
// This is a hanger on from its Delphi origins, it might be dispensable
// given the garbage collection abilities of .NET
private void killTree(ref TTreeNode p)
{
if (p != null)
{
killTree(ref p.left);
killTree(ref p.right);
p = null;
}
}
public TTreeNode(int id, int hsk, double d,int smt)
{
this.oid = id;
dongia = d;
hesok = hsk;
somattien = smt;
left = null;
right = null;
}
// Simple 'drawing' routines
private string drawNode(TTreeNode node)
{
if (node == null)
return "empty";
if ((node.left == null) && (node.right == null))
return node.oid.ToString();
if ((node.left != null) && (node.right == null))
return node.oid.ToString() + "(" + drawNode(node.left) + ", _)";
if ((node.right != null) && (node.left == null))
return node.oid.ToString() + "(_, " + drawNode(node.right) + ")";
return node.oid.ToString() + "(" + drawNode(node.left) + ", " + drawNode(node.right) + ")";
}
// Searches for a node with name key, name. If found it returns a reference
// to the node and to thenodes parent. Else returns null.
private TTreeNode findParent(int obj, ref TTreeNode parent,string key)
{
TTreeNode np = root;
parent = null;
int cmp;
while (np != null)
{
//cmp = String.Compare(name, np.name);
if (key == "hsk")
{
if (obj == np.hesok) // found !
return np;
if (obj < np.hesok)
{
parent = np;
np = np.left;
}
else
{
parent = np;
np = np.right;
}
}
else if (key == "oid")
{
if (obj == np.oid) // found !
return np;
if (obj < np.oid)
{
parent = np;
np = np.left;
}
else
{
parent = np;
np = np.right;
}
}
}
return null; // Return null to indicate failure to find name
}
// Recursively locates an empty slot in the binary tree and inserts the node
private void add(TTreeNode node, ref TTreeNode tree)
{
if (tree == null)
tree = node;
else
{
// If we find a node with the same name then it's
// a duplicate and we can't continue
//int comparison = String.Compare(node.name, tree.name);
if (node.oid==tree.oid)
throw new Exception();
if (node.oid < tree.oid)
{
add(node, ref tree.left);
}
else
{
add(node, ref tree.right);
}
}
}
public void Visit(TTreeNode node)
{
if (node == null)
{
return;
}
_lstOid.Add(node.oid);
_lstHsk.Add(node.hesok);
//MessageBox.Show(string.Format("lien 522 LandpriceInfoTree, len ={0},oid={1}", _lstOid.Count, _lstOid[_lstOid.Count - 1]));
if (node.left != null)
{
Visit(node.left);
}
if(node.right!=null)
{
Visit(node.right);
}
}
public TTreeNode insert(int oid, int hsk, double d)
{
TTreeNode node = new TTreeNode(oid, hsk, d);
try
{
if (root == null)
root = node;
else
add(node, ref root);
_count++;
return node;
}
catch (Exception)
{
return null;
}
}
/// <summary>
/// Find the next ordinal node starting at node startNode.
/// Due to the structure of a binary search tree, the
/// successor node is simply the left most node on the right branch.
/// </summary>
/// <param name="startNode">Name key to use for searching</param>
/// <param name="parent">Returns the parent node if search successful</param>
/// <returns>Returns a reference to the node if successful, else null</returns>
public TTreeNode findSuccessor(TTreeNode startNode, ref TTreeNode parent)
{
parent = startNode;
// Look for the left-most node on the right side
startNode = startNode.right;
while (startNode.left != null)
{
parent = startNode;
startNode = startNode.left;
}
return startNode;
}
/// <summary>
/// Delete a given node. This is the more complex method in the binary search
/// class. The method considers three senarios, 1) the deleted node has no
/// children; 2) the deleted node as one child; 3) the deleted node has two
/// children. Case one and two are relatively simple to handle, the only
/// unusual considerations are when the node is the root node. Case 3) is
/// much more complicated. It requires the location of the successor node.
/// The node to be deleted is then replaced by the sucessor node and the
/// successor node itself deleted. Throws an exception if the method fails
/// to locate the node for deletion.
/// </summary>
/// <param name="key">Name key of node to delete</param>
public void delete(int obj,string key)
{
TTreeNode parent = null;
// First find the node to delete and its parent
TTreeNode nodeToDelete = findParent(obj, ref parent,key);
if (nodeToDelete == null)
throw new Exception("Unable to delete node: " + key.ToString()); // can't find node, then say so
// Three cases to consider, leaf, one child, two children
// If it is a simple leaf then just null what the parent is pointing to
if ((nodeToDelete.left == null) && (nodeToDelete.right == null))
{
if (parent == null)
{
root = null;
return;
}
// find out whether left or right is associated
// with the parent and null as appropriate
if (parent.left == nodeToDelete)
parent.left = null;
else
parent.right = null;
_count--;
return;
}
// One of the children is null, in this case
// delete the node and move child up
if (nodeToDelete.left == null)
{
// Special case if we're at the root
if (parent == null)
{
root = nodeToDelete.right;
return;
}
// Identify the child and point the parent at the child
if (parent.left == nodeToDelete)
parent.right = nodeToDelete.right;
else
parent.left = nodeToDelete.right;
nodeToDelete = null; // Clean up the deleted node
_count--;
return;
}
// One of the children is null, in this case
// delete the node and move child up
if (nodeToDelete.right == null)
{
// Special case if we're at the root
if (parent == null)
{
root = nodeToDelete.left;
return;
}
// Identify the child and point the parent at the child
if (parent.left == nodeToDelete)
parent.left = nodeToDelete.left;
else
parent.right = nodeToDelete.left;
nodeToDelete = null; // Clean up the deleted node
_count--;
return;
}
// Both children have nodes, therefore find the successor,
// replace deleted node with successor and remove successor
// The parent argument becomes the parent of the successor
TTreeNode successor = findSuccessor(nodeToDelete, ref parent);
// Make a copy of the successor node
TTreeNode tmp = new TTreeNode(successor.oid, successor.hesok,successor.dongia,successor.somattien);
// Find out which side the successor parent is pointing to the
// successor and remove the successor
if (parent.left == successor)
parent.left = null;
else
parent.right = null;
// Copy over the successor values to the deleted node position
nodeToDelete.oid = tmp.oid;
nodeToDelete.hesok = tmp.hesok;
nodeToDelete.somattien = tmp.somattien;
nodeToDelete.dongia = tmp.dongia;
_count--;
}
