private static ProcessLaunchContext CreateContextForGetOutput(string fileName, string?args) { return(ProcessLaunchContext.Create( fileName: fileName, args: args, showWindow: false, useShellExecute: false )); }
private static ProcessLaunchContext CreateContextForOpenFile(FileInfo file) { return(ProcessLaunchContext.Create( file: file, args: null, showWindow: true, useShellExecute: true )); }