public void JoyStickClick(object sender, JoystickEventArgs e)
{
byte[] keyState = new byte[256];
user32.GetKeyboardState(keyState);
MatchAndSend(e.Buttons, keyState);
}
/// <summary>
/// 触发按钮按下事件
/// </summary>
/// <param name="e"></param>
protected void OnButtonDown(JoystickEventArgs e)
{
EventHandler <JoystickEventArgs> h = this.ButtonDown;
if (h != null)
{
h(this, e);
}
}
protected void OnMove(JoystickEventArgs e)
{
EventHandler <JoystickEventArgs> h = this.Move;
if (h != null)
{
h(this, e);
}
}
/// <summary>
/// 触发单击事件
/// </summary>
/// <param name="e"></param>
protected void OnClick(JoystickEventArgs e)
{
EventHandler <JoystickEventArgs> h = this.Click;
if (h != null)
{
h(this, e);
}
}
public void JoyStickClick(object sender, JoystickEventArgs e)
{
TextBox textBox = Keyboard.FocusedElement as TextBox;
if (textBox == null)
{
return;
}
KeyStoreInfo keyStore = textBox.DataContext as KeyStoreInfo;
if (keyStore != null)
{
keyStore.SetStoreValue(WinManager.GetClickButton(e.Buttons));
//ItemList.Focus();
}
FinishInput();
}
/// <summary>
/// 触发按钮按下事件
/// </summary>
/// <param name="e"></param>
protected void OnButtonDown(JoystickEventArgs e)
{
EventHandler<JoystickEventArgs> h = this.ButtonDown;
if (h != null) h(this, e);
}
protected void OnMove(JoystickEventArgs e)
{
EventHandler<JoystickEventArgs> h = this.Move;
if (h != null) h(this, e);
}
/// <summary>
/// 触发单击事件
/// </summary>
/// <param name="e"></param>
protected void OnClick(JoystickEventArgs e)
{
EventHandler<JoystickEventArgs> h = this.Click;
if (h != null) h(this, e);
}
public void JoyStickClick(object sender, JoystickEventArgs e)
{
TextBox textBox = Keyboard.FocusedElement as TextBox;
if (textBox == null)
return;
KeyStoreInfo keyStore = textBox.DataContext as KeyStoreInfo;
if (keyStore != null)
{
keyStore.SetStoreValue(WinManager.GetClickButton(e.Buttons));
//ItemList.Focus();
}
FinishInput();
}
public void JoyStickClick(object sender, JoystickEventArgs e)
{
byte[] keyState = new byte[256];
user32.GetKeyboardState(keyState);
MatchAndSend(e.Buttons, keyState);
}
