internal void build_tree(DeflateManager s)
{
short[] tree = dyn_tree;
short[] stree = staticTree.treeCodes;
int elems = staticTree.elems;
int max_code = -1;
s.heap_len = 0;
s.heap_max = HEAP_SIZE;
for (int j = 0; j < elems; j++)
{
if (tree[j * 2] != 0)
{
max_code = (s.heap[++s.heap_len] = j);
s.depth[j] = 0;
}
else
{
tree[j * 2 + 1] = 0;
}
}
int node;
while (s.heap_len < 2)
{
node = (s.heap[++s.heap_len] = ((max_code < 2) ? (++max_code) : 0));
tree[node * 2] = 1;
s.depth[node] = 0;
s.opt_len--;
if (stree != null)
{
s.static_len -= stree[node * 2 + 1];
}
}
this.max_code = max_code;
for (int j = s.heap_len / 2; j >= 1; j--)
{
s.pqdownheap(tree, j);
}
node = elems;
do
{
int j = s.heap[1];
s.heap[1] = s.heap[s.heap_len--];
s.pqdownheap(tree, 1);
int i = s.heap[1];
s.heap[--s.heap_max] = j;
s.heap[--s.heap_max] = i;
tree[node * 2] = (short)(tree[j * 2] + tree[i * 2]);
s.depth[node] = (sbyte)(Math.Max((byte)s.depth[j], (byte)s.depth[i]) + 1);
tree[j * 2 + 1] = (tree[i * 2 + 1] = (short)node);
s.heap[1] = node++;
s.pqdownheap(tree, 1);
}while (s.heap_len >= 2);
s.heap[--s.heap_max] = s.heap[1];
gen_bitlen(s);
gen_codes(tree, max_code, s.bl_count);
}
internal void build_tree(DeflateManager s)
{
short[] array = dyn_tree;
short[] treeCodes = staticTree.treeCodes;
int elems = staticTree.elems;
int num = -1;
s.heap_len = 0;
s.heap_max = HEAP_SIZE;
for (int i = 0; i < elems; i++)
{
if (array[i * 2] != 0)
{
num = (s.heap[++s.heap_len] = i);
s.depth[i] = 0;
}
else
{
array[i * 2 + 1] = 0;
}
}
int num2;
while (s.heap_len < 2)
{
num2 = (s.heap[++s.heap_len] = ((num < 2) ? (++num) : 0));
array[num2 * 2] = 1;
s.depth[num2] = 0;
s.opt_len--;
if (treeCodes != null)
{
s.static_len -= treeCodes[num2 * 2 + 1];
}
}
max_code = num;
for (int i = s.heap_len / 2; i >= 1; i--)
{
s.pqdownheap(array, i);
}
num2 = elems;
do
{
int i = s.heap[1];
s.heap[1] = s.heap[s.heap_len--];
s.pqdownheap(array, 1);
int num3 = s.heap[1];
s.heap[--s.heap_max] = i;
s.heap[--s.heap_max] = num3;
array[num2 * 2] = (short)(array[i * 2] + array[num3 * 2]);
s.depth[num2] = (sbyte)(Math.Max((byte)s.depth[i], (byte)s.depth[num3]) + 1);
array[i * 2 + 1] = (array[num3 * 2 + 1] = (short)num2);
s.heap[1] = num2++;
s.pqdownheap(array, 1);
}while (s.heap_len >= 2);
s.heap[--s.heap_max] = s.heap[1];
gen_bitlen(s);
gen_codes(array, num, s.bl_count);
}
internal void build_tree(DeflateManager s)
{
short[] tree = this.dyn_tree;
short[] numArray1 = this.staticTree.treeCodes;
int num1 = this.staticTree.elems;
int max_code = -1;
s.heap_len = 0;
s.heap_max = Tree.HEAP_SIZE;
for (int index = 0; index < num1; ++index)
{
if ((int)tree[index * 2] != 0)
{
s.heap[++s.heap_len] = max_code = index;
s.depth[index] = (sbyte)0;
}
else
{
tree[index * 2 + 1] = (short)0;
}
}
while (s.heap_len < 2)
{
int[] numArray2 = s.heap;
int index1 = ++s.heap_len;
int num2;
if (max_code >= 2)
{
num2 = 0;
}
else
{
max_code = num2 = max_code + 1;
}
int num3 = num2;
numArray2[index1] = num2;
int index2 = num3;
tree[index2 * 2] = (short)1;
s.depth[index2] = (sbyte)0;
--s.opt_len;
if (numArray1 != null)
{
s.static_len -= (int)numArray1[index2 * 2 + 1];
}
}
this.max_code = max_code;
for (int k = s.heap_len / 2; k >= 1; --k)
{
s.pqdownheap(tree, k);
}
int index3 = num1;
do
{
int index1 = s.heap[1];
s.heap[1] = s.heap[s.heap_len--];
s.pqdownheap(tree, 1);
int index2 = s.heap[1];
s.heap[--s.heap_max] = index1;
s.heap[--s.heap_max] = index2;
tree[index3 * 2] = (short)((int)tree[index1 * 2] + (int)tree[index2 * 2]);
s.depth[index3] = (sbyte)((int)Math.Max((byte)s.depth[index1], (byte)s.depth[index2]) + 1);
tree[index1 * 2 + 1] = tree[index2 * 2 + 1] = (short)index3;
s.heap[1] = index3++;
s.pqdownheap(tree, 1);
}while (s.heap_len >= 2);
s.heap[--s.heap_max] = s.heap[1];
this.gen_bitlen(s);
Tree.gen_codes(tree, max_code, s.bl_count);
}
// Construct one Huffman tree and assigns the code bit strings and lengths.
// Update the total bit length for the current block.
// IN assertion: the field freq is set for all tree elements.
// OUT assertions: the fields len and code are set to the optimal bit length
// and corresponding code. The length opt_len is updated; static_len is
// also updated if stree is not null. The field max_code is set.
internal void build_tree(DeflateManager s)
{
short[] tree = dyn_tree;
short[] stree = stat_desc.static_tree;
int elems = stat_desc.elems;
int n, m; // iterate over heap elements
int max_code = -1; // largest code with non zero frequency
int node; // new node being created
// Construct the initial heap, with least frequent element in
// heap[1]. The sons of heap[n] are heap[2*n] and heap[2*n+1].
// heap[0] is not used.
s.heap_len = 0;
s.heap_max = HEAP_SIZE;
for (n = 0; n < elems; n++)
{
if (tree[n * 2] != 0)
{
s.heap[++s.heap_len] = max_code = n;
s.depth[n] = 0;
}
else
{
tree[n * 2 + 1] = 0;
}
}
// The pkzip format requires that at least one distance code exists,
// and that at least one bit should be sent even if there is only one
// possible code. So to avoid special checks later on we force at least
// two codes of non zero frequency.
while (s.heap_len < 2)
{
node = s.heap[++s.heap_len] = (max_code < 2?++max_code:0);
tree[node * 2] = 1;
s.depth[node] = 0;
s.opt_len--;
if (stree != null)
{
s.static_len -= stree[node * 2 + 1];
}
// node is 0 or 1 so it does not have extra bits
}
this.max_code = max_code;
// The elements heap[heap_len/2+1 .. heap_len] are leaves of the tree,
// establish sub-heaps of increasing lengths:
for (n = s.heap_len / 2; n >= 1; n--)
{
s.pqdownheap(tree, n);
}
// Construct the Huffman tree by repeatedly combining the least two
// frequent nodes.
node = elems; // next internal node of the tree
do
{
// n = node of least frequency
n = s.heap[1];
s.heap[1] = s.heap[s.heap_len--];
s.pqdownheap(tree, 1);
m = s.heap[1]; // m = node of next least frequency
s.heap[--s.heap_max] = n; // keep the nodes sorted by frequency
s.heap[--s.heap_max] = m;
// Create a new node father of n and m
tree[node * 2] = (short)(tree[n * 2] + tree[m * 2]);
s.depth[node] = (sbyte)(System.Math.Max((byte)s.depth[n], (byte)s.depth[m]) + 1);
tree[n * 2 + 1] = tree[m * 2 + 1] = (short)node;
// and insert the new node in the heap
s.heap[1] = node++;
s.pqdownheap(tree, 1);
}while (s.heap_len >= 2);
s.heap[--s.heap_max] = s.heap[1];
// At this point, the fields freq and dad are set. We can now
// generate the bit lengths.
gen_bitlen(s);
// The field len is now set, we can generate the bit codes
gen_codes(tree, max_code, s.bl_count);
}
// Construct one Huffman tree and assigns the code bit strings and lengths.
// Update the total bit length for the current block.
// IN assertion: the field freq is set for all tree elements.
// OUT assertions: the fields len and code are set to the optimal bit length
// and corresponding code. The length opt_len is updated; static_len is
// also updated if stree is not null. The field max_code is set.
internal void build_tree(DeflateManager s)
{
short[] tree = dyn_tree;
short[] stree = staticTree.treeCodes;
int elems = staticTree.elems;
int n, m; // iterate over heap elements
int max_code = -1; // largest code with non zero frequency
int node; // new node being created
// Construct the initial heap, with least frequent element in
// heap[1]. The sons of heap[n] are heap[2*n] and heap[2*n+1].
// heap[0] is not used.
s.heap_len = 0;
s.heap_max = HEAP_SIZE;
for (n = 0; n < elems; n++)
{
if (tree[n * 2] != 0)
{
s.heap[++s.heap_len] = max_code = n;
s.depth[n] = 0;
}
else
{
tree[n * 2 + 1] = 0;
}
}
// The pkzip format requires that at least one distance code exists,
// and that at least one bit should be sent even if there is only one
// possible code. So to avoid special checks later on we force at least
// two codes of non zero frequency.
while (s.heap_len < 2)
{
node = s.heap[++s.heap_len] = (max_code < 2?++max_code:0);
tree[node * 2] = 1;
s.depth[node] = 0;
s.opt_len--;
if (stree != null)
s.static_len -= stree[node * 2 + 1];
// node is 0 or 1 so it does not have extra bits
}
this.max_code = max_code;
// The elements heap[heap_len/2+1 .. heap_len] are leaves of the tree,
// establish sub-heaps of increasing lengths:
for (n = s.heap_len / 2; n >= 1; n--)
s.pqdownheap(tree, n);
// Construct the Huffman tree by repeatedly combining the least two
// frequent nodes.
node = elems; // next internal node of the tree
do
{
// n = node of least frequency
n = s.heap[1];
s.heap[1] = s.heap[s.heap_len--];
s.pqdownheap(tree, 1);
m = s.heap[1]; // m = node of next least frequency
s.heap[--s.heap_max] = n; // keep the nodes sorted by frequency
s.heap[--s.heap_max] = m;
// Create a new node father of n and m
tree[node * 2] = unchecked((short) (tree[n * 2] + tree[m * 2]));
s.depth[node] = (sbyte) (System.Math.Max((byte) s.depth[n], (byte) s.depth[m]) + 1);
tree[n * 2 + 1] = tree[m * 2 + 1] = (short) node;
// and insert the new node in the heap
s.heap[1] = node++;
s.pqdownheap(tree, 1);
}
while (s.heap_len >= 2);
s.heap[--s.heap_max] = s.heap[1];
// At this point, the fields freq and dad are set. We can now
// generate the bit lengths.
gen_bitlen(s);
// The field len is now set, we can generate the bit codes
gen_codes(tree, max_code, s.bl_count);
}
internal void build_tree(DeflateManager s)
{
int num2;
int num5;
short[] tree = this.dyn_tree;
short[] numArray2 = this.stat_desc.static_tree;
int elems = this.stat_desc.elems;
int num4 = -1;
s.heap_len = 0;
s.heap_max = HEAP_SIZE;
for (num2 = 0; num2 < elems; num2++)
{
if (tree[num2 * 2] != 0)
{
s.heap[++s.heap_len] = num4 = num2;
s.depth[num2] = 0;
}
else
{
tree[(num2 * 2) + 1] = 0;
}
}
while (s.heap_len < 2)
{
num5 = s.heap[++s.heap_len] = (num4 < 2) ? ++num4 : 0;
tree[num5 * 2] = 1;
s.depth[num5] = 0;
s.opt_len--;
if (numArray2 != null)
{
s.static_len -= numArray2[(num5 * 2) + 1];
}
}
this.max_code = num4;
num2 = s.heap_len / 2;
while (num2 >= 1)
{
s.pqdownheap(tree, num2);
num2--;
}
num5 = elems;
do
{
num2 = s.heap[1];
s.heap[1] = s.heap[s.heap_len--];
s.pqdownheap(tree, 1);
int index = s.heap[1];
s.heap[--s.heap_max] = num2;
s.heap[--s.heap_max] = index;
tree[num5 * 2] = (short)(tree[num2 * 2] + tree[index * 2]);
s.depth[num5] = (sbyte)(Math.Max((byte)s.depth[num2], (byte)s.depth[index]) + 1);
tree[(num2 * 2) + 1] = tree[(index * 2) + 1] = (short)num5;
s.heap[1] = num5++;
s.pqdownheap(tree, 1);
}while (s.heap_len >= 2);
s.heap[--s.heap_max] = s.heap[1];
this.gen_bitlen(s);
gen_codes(tree, num4, s.bl_count);
}